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\(7.3^x+20.3^x=3^{25}\)
\(3^x.\left(7+20\right)=3^{25}\)
\(3^x.3^3=3^{25}\)
\(3^x=3^{22}\)
\(\Rightarrow x=22\)
7.3x+20.3x=325
\(\Leftrightarrow\)3x . ( 7 + 20 ) = 325
\(\Leftrightarrow\)3x . 27 = 325
\(\Leftrightarrow\)3x . 33 = 325
\(\Leftrightarrow\)3x = 325 : 33
\(\Leftrightarrow\)3x = 325 - 3
\(\Leftrightarrow\)3x = 323
\(\Leftrightarrow\)x = 23
Vậy x = 23
b.\(3^{x+2}\)+4.\(3^{x+1}\)=7.\(3^6\)
\(3^2\).\(3^x\)+4.3.\(3^x\)=7.\(3^6\)
9.\(3^x\)+12.\(3^x\)=7.\(3^6\)
\(3^x\)(9+12)=7.\(3^6\)
\(3^x\).21=7.\(3^6\)
\(3^x\)=7.\(3^6\):21
\(3^x\)=\(3^6\):3
\(3^x\)=\(3^5\)
x=5
32x-2 - 7 . 32 = 32 . 2
32x-2 - 7 . 9 = 9 . 2
32x-2 - 63 = 18
32x-2 = 18 + 63
32x-2 = 81
32x-2 = 34
=> 2x - 2 = 4
2x = 4 + 2
2x = 6
x = 6 : 2
x = 3
lời giải đúng hơi dài
=3^2.(x-1)-7.3^2=3^2.2
chia ca hai vế cho3^2
3^(x-1)-7=2
3^(x-1)=3^2=> x=3
xin lỗi tớ không thể trả lời câu hỏi của bạn được vì tớ mới học lớp 5 thôi tớ không trả lời câu hoi cua ban được thì bạn có thể kết bạn với mình ok
\(\left(7x-2^7:2^3\right):5+7.3=29\)
\(\Rightarrow\left(7x-2^{7-3}\right):5+21=29\)
\(\Rightarrow\left(7x-2^4\right):5=8\)
\(\Rightarrow7x-2^4=40\)
\(\Rightarrow7x=40+2^4=40+16\)
\(\Rightarrow7x=56\)
\(\Rightarrow x=8\)
Vậy x = 8
(7x - 27 : 23) : 5+ 7.3 = 29
( 7x - 24) : 5 + 21 = 29
(7x-16) :5 = 29-21
( 7x-16) :5 =8
7x-16 = 8.5
7x-16 = 40
7x = 40+16
7x = 56
x = 56:7
x=8
a, \(11^{25}\div11^{23}-3^5\div\left(1^{10}+2^3\right)-60\)
\(=11^{25}\div11^{23}-3^5\div\left(1+8\right)-60\)
\(=11^{25}\div11^{23}-3^5\div3^2-60\)
\(=11^2-3^3-60\)
\(=121-27-60\)
\(=94-60=34\)
b, \(2345-1000\div\left[19-2\left(21-18\right)^2\right]\)
\(=2345-1000\div\left[19-2.3^2\right]\)
\(=2345-1000\div\left[19-2.9\right]\)
\(=2345-1000\div1=2345-1000=1345\)
c, \(128-\left[68+8\left(37-35\right)^2\right]\div4\)
\(=128-\left[68+8.2^2\right]\div4\)
\(=128-\left[68+8.4\right]\div4\)
\(=128-\left[68+32\right]\div4\)
\(=128-100\div4=128-25=103\)
d, \(107-\left\{38+\left[7.3^2-24\div6+\left(9-7\right)^3\right]\right\}\div15\)
\(=107-\left\{38+\left[7.9-4+2^3\right]\right\}\div15\)
\(=107-\left\{38+\left[63-4+8\right]\right\}\div15\)
\(=107-\left\{38+\left[59+8\right]\right\}\div15\)
\(=107-\left\{38+67\right\}\div15\)
\(=107-105\div15\)
\(=107-7=100\)
e, \(50-\left[50-\left(2^3.5\right)\div2+3\right]\)
\(=50-\left[50-8.5\div2+3\right]\)
\(=50-\left[50-40\div2+3\right]\)
\(=50-\left[50-20+3\right]\)
\(=50-\left[30+3\right]\)
\(=50-33=17\)
Bài 2 :
a, \(5\left(x-9\right)=350-5^2\)
\(5\left(x-9\right)=350-25\)
\(5\left(x-9\right)=325\)
\(x-9=325\div5\)
\(x-9=65\)
\(\Rightarrow x=65+9\)
\(\Rightarrow x=74\)
Vậy x = 74
b, \(2\left(x-51\right)=2.2^3+20\)
\(2\left(x-51\right)=16+20\)
\(2\left(x-51\right)=36\)
\(x-51=36\div2\)
\(x-51=18\)
\(\Rightarrow x=18+51\)
\(\Rightarrow x=69\)
Vậy x = 69
c, \(2.3^x=162\)
\(\Rightarrow2.3^x=2.3^4\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy x = 4
7 . 3x + 20 . 3x = 325
=> 3x ( 7+20) = 325
=> 3x . 27 = 325
=> 325-x = 27 = 33
=> 25 - x = 3
=> x = 25 - 3 = 22
\(7.3^x+20.3^x=3^{25}\)
\(\Rightarrow3^x\left(7+20\right)=3^{25}\)
\(\Rightarrow3^x.27=3^{25}\)
\(\Rightarrow3^x.3^3=3^{25}\)
\(\Rightarrow3^{x+3}=3^{25}\Rightarrow x+3=25\Rightarrow x=22\)