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a) \(\frac{17}{9}-\frac{17}{9}:\left(\frac{7}{3}+\frac{1}{2}\right)\)
= \(\frac{17}{9}-\frac{17}{9}:\frac{17}{6}\)
= \(\frac{17}{9}-\frac{2}{3}\)
= \(\frac{11}{9}\)
b) \(\frac{4}{3}.\frac{2}{5}-\frac{3}{4}.\frac{2}{5}\)
= \(\frac{2}{5}.\left(\frac{4}{3}-\frac{3}{4}\right)\)
= \(\frac{2}{5}.\frac{7}{12}\)
= \(\frac{7}{30}\)
Mình lười làm quá, hay mình nói kết quả cho bn thôi nha
c) -6
d) 3
e) 3
g) 12
h) \(\frac{23}{18}\)
i) \(\frac{-69}{20}\)
k) \(\frac{-1}{2}\)
l) \(\frac{49}{5}\)
a ) \(\frac{-5}{9}:\frac{-7}{18}+1\frac{2}{7}\)
\(=\frac{-5}{9}.-\frac{18}{7}+\frac{9}{7}\)
\(=\frac{-5.-18}{9.7}+\frac{9}{7}\)
\(=\frac{10}{7}+\frac{9}{7}\)
\(=\frac{10+9}{7}\)
\(=\frac{19}{7}\)
\(\frac{2^{27}\times9^4}{6^9\times8^5}=\frac{2^{27}\times\left(3^2\right)^4}{\left(2\times3\right)^9\times\left(2^3\right)^5}=\frac{2^{27}\times3^8}{2^9\times3^9\times2^{15}}=\frac{2^3}{3}=\frac{8}{3}\)
\(\sqrt{13^2}-5^2+\sqrt{3^2+4^2}-\sqrt{\left(-7\right)^2}=13-25+\sqrt{9+16}-\sqrt{49}=13-25+5-7=-14\)
i) \(\frac{25^9}{5^{16}}-5^3:5\)
\(=\frac{\left(5^2\right)^9}{5^{16}}-5^2\)
\(=\frac{5^{18}}{5^{16}}-25\)
\(=5^2-25\)
\(=25-25\)
\(=0.\)
k) \(\frac{5}{7}-\left|\frac{2}{-7}\right|\)
\(=\frac{5}{7}-\left|\frac{-2}{7}\right|\)
\(=\frac{5}{7}-\frac{2}{7}\)
\(=\frac{3}{7}.\)
l) \(\frac{3^6.3^4}{9^3}\)
\(=\frac{3^{6+4}}{\left(3^2\right)^3}\)
\(=\frac{3^{10}}{3^6}\)
\(=3^4.\)
\(=81.\)
Chúc bạn học tốt!
\(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
\(=\frac{1}{3}+\frac{1}{4}\)
\(=\frac{7}{12}\)
\(6\frac{4}{5}:\frac{3}{7}+\frac{27}{5}:\sqrt{\frac{9}{49}}\)
\(=\frac{34}{5}:\frac{3}{7}+\frac{27}{5}:\frac{3}{7}\)
\(=\frac{34}{5}\cdot\frac{7}{3}+\frac{27}{5}\cdot\frac{7}{3}\)
\(=\frac{7}{3}\left(\frac{34}{5}+\frac{27}{5}\right)\)
\(=\frac{7}{3}\cdot12=28\)