Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)47-[(45x24-52x12):14]
=47-[(45x16-25x12):14]
=47-[(720-300):14]
=47-[420:14]
=47-30
=17
b)695-[200+(11-1)2]
=695-[200+102]
=695-[200+100]
=695-300
=395
tick hộ nha
a. 4 . 5 + 28 : 7 - 620 : 618
= 20 + 4 - 62
= 20 + 4 - 36
= .... ( tự làm )
b. 718 : 716 + 22 . 33
= 72 + 25
= 49 + 32
= ...
c. 59 : 57 + 12 . 3 + 70
= 52 + 36 + 0
= ...
d. 205 - [ 1200 - ( 42 - 2 . 3 )3 ]
= 205 - [ 1200 - 103 ]
= 205 - [ 1200 - 100 ]
= ...
e. 695 - [ 200 - ( 11 - 1 )2 ]
= 695 - [ 200 - 102 ]
= 695 - [ 200 - 100 ]
= ...
#A?m?
sai hết r bạn ơi
phải là
a)28
b)157
c)62
d)5
e)598
ko có số âm đâu
\(695-\left[200+\left(11-1\right)^2\right]=695-\left[200+100\right]=695-300=395\)
Ta có : \(695-\left(200+\left(11-1\right)^2\right)\)
\(=695-\left(200+10^2\right)=695-\left(200+100\right)\)
\(=695-300=395\)
\(a)47-\left[\left(45.2^4-5^2.12\right):14\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]\)
\(=47-30\)
\(=17\)
\(b)50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right)\right]:2+34\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]\)
\(=50-40\)
\(=10\)
\(c)10^2-\left[60:\left(5^6:5^4-3,5\right)\right]\)
\(=10^2-\left[60:\left(5^2-3,5\right)\right]\)
\(=10^2-\left[60:\left(25-3,5\right)\right]\)
\(=10^2-\left[60:21,5\right]\)
\(=100-\dfrac{120}{43}\)
\(=\dfrac{4180}{43}\)
\(d)50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left[10:2+3\right]\)
\(=50-5+3\)
\(=50-8\)
\(=42\)
\(e)10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
\(f)8697-\left[3^7:3^5+2.\left(13-3\right)\right]\)
\(=8697-\left[3^2+2.\left(13-3\right)\right]\)
\(=8697-\left[9+2.10\right]\)
\(=8697-9+20\)
\(=8697-29\)
\(=8668\)
\(g)2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-10^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
\(h)695-\left[200+\left(11-1\right)^2\right]\)
\(=695-\left[200+10^2\right]\)
\(=695-200+100\)
\(=695-300\)
\(=395\)
\(i)129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\left[29-25\right]\)
\(=129-5.4\)
\(=129-20\)
\(=109\)
659 - [ 200 + (11-1) . 2 ]
= 659 - [ 200 + 10 . 2 ]
= 659 - [ 200 + 20 ]
= 659 - 220
= 439
1, A = 291 = 27.13 = (213)7 = 81927
B = 535 = 55.7 = (55)7 = 31257
Vì 3125 < 8192
=> 31257 < 81927
=> B < A
2.Ta có:
A=11+112+113+114+...+11199+11200.
11A=112+113+114+...+11199+11200+11201.
11A-A=11201-11.
10A=11201-11.
A=(11201-11):10
Quan sát 2 vế A và B thì ta thấy rõ ràng vế A<B hay B>A.
=> 2x-1=9=>x=5 (7x-11)^3=32x25+200
=>2x-1=-9=>x=-4 (7x-11)^3=1000
=>7x-11=10
=>7x=21
=>x=3
Ta có
(2x+1)2 =81
=>(2x+1)2= 92
=> 2x+1=9 (1)
Hoặc 2x+1=-9 (2)
Từ (1) => 2x+1=9
=>2x= 9-1
=>2x=8
=>x=8:2
=>x=4
Từ (2)=> 2x+1=-9
=>2x=-9-1
=>2x=-10
=>x=-10:2
=>x=- 5
Vậy x€{-5;4}
a) 47 - [(45.16 - 25.12 ) : 14]
= 47 - [ (720 - 300 ) : 14
= 47 - [ 420 : 14 ]
= 47 - 30
= 17
b) 50 - [ (20 - 8 ) : 2 + 34 ]
= 50 - [ 12 : 2 + 34 ]
= 50 - [ 6 + 34 ]
= 50 - 40
= 10
c) 100 - [ 60 : ( 15625 : 625 - 15 )
= 100 - [ 60 : ( 25 - 15 ) ]
= 100 - [ 60 : 10 ]
= 100 - 6
= 94
d)50-[(50-235)/2+3
=50-(10/2+3)
=50-8
=42
minh chi giupban duoc den do thoi ha
\(695-\left[200+\left(11-1^2\right)\right]\\ =695-\left[200+\left(11-1\right)\right]\\ =695-\left(200+10\right)\\ =695-210\\ =485\)
= 695 - [200 + 102 ]
= 695 - 300
=395