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\(5^x+5^{x+1}+5^{x+2}=155\)
\(\Rightarrow5^x+5^x.5+5^x.25=155\)
\(\Rightarrow5^x\left(1+5+25\right)=155\)
\(\Rightarrow5^x=155:31=5=5^1\)
\(\Rightarrow x=1\)
Vậy x = 1
=5^x*1+5^x*5^1+5^x*5^2=155
=5^x*(1+5+25)=155
=5^x=155/31
=5^x=5
=x=1
\(5^{x+1}+5^{x+2}+5^{x+3}=155\)
\(\Leftrightarrow5^{x+1}\left(1+5+5^2\right)=155\)
\(\Leftrightarrow5^{x+1}\cdot31=155\)
\(\Leftrightarrow5^{x+1}=5\)
\(\Leftrightarrow x+1=1\)
\(\Leftrightarrow x=0\)
Vậy....
a)=>48+288:(x-3)^2=50
=>288:(x-3)^2=2
=>(x-3)^2=144
=>x-3=12=>x=15
5 ^ x + 1 + 5 ^ x + 2 + 5 ^ x + 3 = 155
=> 5 ^ x + 1 . ( 1 + 5 + 5 ^ 2 ) = 155
=> 5 ^ x + 1 . 31 = 155
=> 5 ^ x + 1 = 155 : 31
=> 5 ^ x + 1 = 5
=> x + 1 = 1
=> x = 0
a/ 22(x + 32) - 5 = 55 b/ 155 - 10(x+1) = 55
4(x + 32) = 60 10(x + 1) = 100
x + 32 = 60 : 4 x + 1 = 10
x + 32 = 15 x = 10 - 1
x = 15 - 32 x = 9
x = - 17
c/ 5. 22 + (x+3) = 52 53 - 5 (4 + x) = 15
20 + (x+3) = 25 125 - 5(4 +x) = 15
x+ 3 = 5 5(4 + x) = 110
x = 5-3 4 + x= 110 : 2
x = 2 4 + x = 55
x = 51
ủng hộ mk nha !!!! ^_^
a, \(\left(2x+7\right)^4=10^{11}:10^7\)
\(\Rightarrow\left(2x+7\right)^4=10^4\)
\(\Rightarrow2x+7=10\)
\(\Rightarrow2x=10-7\)
\(\Rightarrow2x=3\)
\(\Rightarrow x=\dfrac{3}{2}\) hay \(x=1,5\)
b, \(5^{x-1}.7^{x-1}=25.49\)
\(\Rightarrow\)\(5^{x-1}.7^{x-1}=5^2.7^2\)
\(\Rightarrow\left\{{}\begin{matrix}5^{x-1}=5^2\\7^{x-1}=7^2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x-1=2\\x-1=2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=3\\x=3\end{matrix}\right.\)
c, \(\left(x-5\right)^{2018}=9.\left(x-5\right)^{2016}\)
\(\Rightarrow\dfrac{\left(x-5\right)^{2018}}{\left(x-5\right)^{2016}}=9.\dfrac{\left(x-5\right)^{2016}}{\left(x-5\right)^{2016}}\)
\(\Rightarrow\left(x-5\right)^2=9\)
\(\Leftrightarrow\left(x-5\right)^2=3^2\)
\(\Rightarrow x-5=3\)
\(\Rightarrow x=3+5\)
\(\Rightarrow x=8\)
5x + 5x+1 +5x+3 =155
5x +5x .5 +5x. 52 =155
5x (1+5+25 ) = 155
5x . 31= 155
5x =155: 31
5x=5
5x=51
=> x =1
Vậy x =1