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Ta có: 5x+1=750-5x
\(\Leftrightarrow\)5x+1+5x=750
\(\Leftrightarrow\)5x.6=750
\(\Leftrightarrow\)5x=125
\(\Leftrightarrow\)5x=53
\(\Leftrightarrow\)x=3
Vậy .......
Hok tốt
k mk nha
Ta có:5x+1=750-5x
\(\Rightarrow\)5x.5+5x=750
\(\Rightarrow\)5x.6=750
\(\Rightarrow\)5x=125
\(\Rightarrow\)5x=53
\(\Rightarrow\)x=3
Vậy x=3
5^x + 1 = 750 - 5^x
=> 5^x + 1 + 5^x = 750
=> 5^x(5 + 1) = 750
=> 5^x.6 = 750
=> 5^x = 125
=> x = 3
5x+1=750-5x
5x+1+5x=750
5x.5+5x=750
5x.(5+1)=750
5x.6=750
5x=750:6
5x=125
5x=53
\(\rightarrow\)x=3
vậy x=3
5x + 5x+1 = 750
5x . ( 1 + 5 ) = 750
5x . 6 = 750
5x = 750 : 6
5x = 125
5x = 53
Suy ra : x = 3
\(a,\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x+11\right)^3=32.25+200.\)
\(\left(7x+11\right)^3=800+200.\)
\(\left(7x-11\right)^3=1000.\)
\(\left(7x-11\right)^3=10^3.\)
\(\Rightarrow7x-11=10.\)
\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)
Vậy.....
\(b,3^x+25=26.2^2+2.3^0.\)
\(3^x+25=26.4+2.\)
\(3^x+25=104+2.\)
\(3^x+25=106.\)
\(3^x=106-25.\)
\(3^x=81.\)
\(3^x=3^4\Rightarrow x=4\in Z.\)
Vậy.....
\(c,2^x+3.2=64.\)(có vấn đề).
\(d,5^{x+1}+5^x=750.\)
\(5^x.5^1+5^x+1=750.\)
\(5^x\left(5^1+1\right)=750.\)
\(5^x\left(5+1\right)=750.\)
\(5^x.6=750.\)
\(5^x=750:6.\)
\(5^x=125.\)
\(5^x=5^3\Rightarrow x=3\in Z.\)
Vậy.....
\(e,x^{15}=x.\)
\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)
\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)
\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)
\(6-x=0\Rightarrow x=6\in Z.\)
\(x-4=0\Rightarrow x=4\in Z.\)
Vậy.....
5x + 5x+1 = 750 => 5x + 5x . 5 =750 => 5x . (1 + 5) = 750 => 5x . 6 = 750 => 5x = 750 : 6 => 5x = 125 => 5x = 53 => x = 3
Ta có: \(5^{x+2}+5^{x+3}=750\)
\(\Leftrightarrow5^x\cdot\left(5^2+5^3\right)=750\)
\(\Leftrightarrow5^x\cdot150=750\)
\(\Leftrightarrow5^x=5\)
\(\Rightarrow x=1\)
5x+2 + 5x+3 = 750
<=> 5x . 52 + 5x . 53 = 750
<=> 5x (52 + 53) = 750
<=> 5x (25 + 125) = 750
<=> 5x . 150 = 750
<=> 5x = 750 : 150
<=> 5x = 5
<=> x = 1
#Học tốt!!!
~NTTH~