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a) \(70-5\left(x-3\right)=45\)
\(5\left(x-3\right)=25\)
\(x-3=5\)
\(\Rightarrow x=8\)
b) \(12+\left(5+x\right)=20\)
\(5+x=8\)
\(\Rightarrow x=3\)
c) \(130-\left(100+x\right)=25\)
\(100+x=105\)
\(\Rightarrow x=5\)
d) \(175+\left(30-x\right)=200\)
\(30-x=25\)
\(\Rightarrow x=5\)
e) \(5\left(x+12\right)+22=92\)
\(5\left(x+12\right)=70\)
\(x+12=14\)
\(\Rightarrow x=2\)
a. 70 - 5.(x - 3) = 45
5.(x - 3) = 70 - 45
x - 3 = 25 : 5
x = 5 + 3
x = 8
b. 12 + (5 + x) = 20
5 + x = 20 - 12
x = 8 - 5
x = 3
c. 130 - (100 + x) = 25
100 + x = 130 - 25
x = 105 - 100
x = 5
d. 175 + (30 - x) = 200
30 - x = 200 - 175
x = 30 - 25
x = 5
e. 5.(x + 12) + 22 = 92
5.(x + 12) = 92 - 22
x + 12 = 70 : 5
x = 14 - 12
x = 2
( -12 + 22 ) + ( 5 - 15 )
= 10 - 10
= 0
( x - 3 ) . 5 + 2 . 2 . 2 . 2 = 36
( x - 3 ) . 5 + 16 = 36
( x - 3 ) . 5 = 20
( x - 3 ) = 20 : 5
( x - 3 ) = 4
x = 7
Vậy x = 7
a) \(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(\Rightarrow-12x+60+21-7x=5\)
\(\Rightarrow-19x+81=5\)
\(\Rightarrow-19x=-76\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
b) \(30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(\Rightarrow30x+60-6x+30-24x=100\)
\(\Rightarrow0x+90=100\)
\(\Rightarrow0x=10\)(Vô lí)
Vậy không có x
a; \(\dfrac{93}{17}\): \(x\) + (- \(\dfrac{21}{17}\)) : \(x\) + \(\dfrac{22}{7}\): \(\dfrac{22}{3}\) = \(\dfrac{5}{14}\)
\(\dfrac{94}{17}\) \(\times\) \(\dfrac{1}{x}\) - \(\dfrac{21}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)
\(\dfrac{72}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)
\(\dfrac{72}{17x}\) = \(\dfrac{5}{14}\) - \(\dfrac{3}{7}\)
\(\dfrac{72}{17x}\) = - \(\dfrac{1}{14}\)
17\(x\) = 72.(-14)
17\(x\) = - 1008
\(x\) = - 1008 : 17
\(x\) = - \(\dfrac{1008}{17}\)
Vậy \(x\) \(=-\dfrac{1008}{17}\)
b; - \(\dfrac{32}{27}\) - (3\(x\) - \(\dfrac{7}{9}\))3 = - \(\dfrac{24}{27}\)
- \(\dfrac{32}{27}\) + \(\dfrac{24}{27}\) = (3\(x\) - \(\dfrac{7}{9}\))3
(3\(x-\dfrac{7}{9}\))3 = - \(\dfrac{8}{27}\)
(3\(x-\dfrac{7}{9}\))3 = (- \(\dfrac{2}{3}\))3
3\(x-\dfrac{7}{9}\) = - \(\dfrac{2}{3}\)
3\(x\) = - \(\dfrac{2}{3}\) + \(\dfrac{7}{9}\)
3\(x\) = \(\dfrac{1}{9}\)
\(x\) = \(\dfrac{1}{9}\) : 3
\(x\) = \(\dfrac{1}{27}\)
Vậy \(x=\dfrac{1}{27}\)
2x+20=-22
=> 2x = -22 - 20
=> 2x = -42
=> x = -42 : 2
=> x = -21
Vậy x = -21
2x+20=-22
2x=-22-20
2x=-42
x=-42:2
x=-21
-(-30)-(-x)=13
30+x=13
x=13-30
x=-17
-(-x)+14=12
x+14=12
x=12-14
x=-2
x+20=-(-23)
x+20=23
x=23-20
x=3
15-x+17=-(-6)+|-12|
15+17+x=6+12
32+x=18
x=18-32
x=-14
-|-5|-(-x)+4=3-(-25)
-5+x+4=3+25
-5+4+x=28
-1x=28
x=28:(-1)
x=-28
a)Ta có:
\(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(\Rightarrow-12x+60+21-7x=5\)
\(\Rightarrow60+21-5=12x+7x\)
\(\Rightarrow76=19x\Rightarrow x=4\)
b)Ta có:
\(30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(\Rightarrow30x+60-6x+30-24x=100\)
\(\Rightarrow30x-6x-24x=100-60-30\)
\(\Rightarrow0x=10\), vô lí
Vậy không có x thỏa mãn
5(3-x)+12=22
5(3-x)=10
3-x=3
x=0
5(3-x) = 22-12
5.3 - 5.x = 10
15 - 5x =10
5x = 15 -10
5x = 5
x = 1
vậy x = 1
k nha