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4x + 1+ 40= 65
4x + 1+ 1 = 65
4x + 1 = 65 - 1
4x + 1 = 64
43 = 64
x = 3 - 1
x = 2
4x+1 + 40 = 65
4x+1 + 1 = 65
4x+1 = 65 - 1
4x+1 = 64
4x+1 = 43
=> X + 1 = 3
X = 3 - 1
X = 2
Vậy X = 2
Ủng hộ mk nha !!! ^_^
1, 4\(^{x+1}\) + 4\(^0\) = 65
\(\Rightarrow\)4\(^{x+1}\) = 65 - 1
\(\Rightarrow\)x + 1 = 64 : 4
\(\Rightarrow\)x + 1 = 16
\(\Rightarrow\)x = 15
2) 10 + 2x = 16\(^{^2}\): 4\(^3\)
\(\Rightarrow\)10 + 2x = 4
\(\Rightarrow\)2x = 4 - 10
\(\Rightarrow\)2x = -6
\(\Rightarrow\)x = -3
tiểu linh miêu:
1) 137 . 68 + 16 . 272 - 68
= 68 . (137 - 1) + 16 . 272
= 68 . 136 + 4352
= 9248 + 4352
= 13600
2) 4x + 1 + 1 = 65
4x + 1 = 65 - 1
4x + 1 = 64
4x -+ 1 = 43
=> x + 1 = 3
=> x = 2
^_^, Chúc bạn học tốt!!!
4x + 1 + 40 = 65
4x + 1 + 1 = 65
4x + 1 = 64 = 44
=> x + 1 = 4
=> x = 3
Ta có: \(4^{x+1}+1=65\)
\(\Rightarrow4^{x+1}=64\)
\(\Rightarrow4^{x+1}=4^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=3-1=2\)
k cho mình nha cảm ơn nhìu
\(65-4^{x+1}=2019^0\)
\(\Rightarrow65-4^{x+1}=1\)
\(\Rightarrow4^{x+1}=65-1\)
\(\Rightarrow4^{x+1}=64\)
\(\Rightarrow4^{x+1}=4^3\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=4-1\)
\(\Rightarrow x=3\)
Vậy x = 3
_Chúc bạn học tốt_
\(65-4^{x+1}=2019^0\)
\(65-4^x.4=1\)
\(4^x.4=65-1\)
\(4^x.4=64\)
\(4^x=64:4\)
\(4^x=16\)
\(4^x=4^2\)
\(\Rightarrow x=2\)
4x+1 + 40 = 65
4x+1 + 1 = 65
4x+1 = 64
4x-1 = 43
=> x - 1 = 3
=> x = 4
Vậy x = 4
a,10+2x=45:43
10+2x=42
10+2x=16
2x=16-10
2x=6
x=6:2
x=3
b,310-(20-x)=300
20-x =310-300
20-x =10
x=20-10
x=10
c,4x+1+40=65
4x+1+40=65
4x+1+1 =65
4x+1 =65-1
4x+1 =64
4x+1 =43
x =3-1
=> x =2
a) 10 + 2x = 45 : 43
10 + 2x = 42 = 16
2x = 16 - 10
2x = 6
x = 3
b) 310 - (20 - x) = 300
310 - 20 + x = 300
290 + x = 300
x = 300 - 290
x = 10
c) 4x + 1 + 40 = 65
4x + + 1 = 65
4x + 1 = 64 = 43
=> x + 1 = 3
=> x = 2
1. Tính theo cách hợp lí:
\(2016.5^{2017}.\left(30.5^{2015}-5^{2016}\right)\)
\(=2016.5^{2017}.5^{2015}.\left(30-5\right)\)
\(=2016.5^{4032}.25\)
\(=2016.5^{4032}.5^2\)
\(=2016.5^{4034}\)
2. Tìm x:
\(4^{x+1}+4^0=65\)
\(\Leftrightarrow4^{x+1}+1=65\)
\(\Leftrightarrow4^{x+1}=65-1\)
\(\Leftrightarrow\left(2^2\right)^{x+1}=64\)
\(\Leftrightarrow2^{2x+2}=2^6\)
\(\Rightarrow2x+2=6\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2.\)
(4 + x) . 33 = 35
4 + x = 35 : 33
4 + x = 32
4 + x = 9
x = 9 - 4
x = 5
65 - 4x - 3 = 20200
65 - 4x - 3 = 1
65 - 4x = 1 + 4
65 - 4x = 5
4x = 65 - 5
4x = 50
x = 60 : 4
x = 15
(4 + x) . 33 = 35
(4 + x) = 35 : 33
4 + x = 32
4 + x = 9
x = 9 - 4
x = 5
Vậy x = 5
\(4^{x+1}+4^0=65\)
\(4^{x+1}+1=65\)
\(4^{x+1}=65-1\)
\(4^{x+1}=64\)
\(4^{x+1}=4^3\)
=> X+1=3
x =2
Vậy x=2
\(4^{x+1}\) + \(4^0\) = 65
\(\Rightarrow\) \(4^{x+1}\) + 1 = 65
\(\Rightarrow\) \(4^{x+1}\) = 65 - 1 = 64 = \(4^3\)
\(\Rightarrow\) x + 1 = 3
\(\Rightarrow\) x = 3 - 1 = 2
Vậy x = 2 .