Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, \(\frac{25^{11}.4^{33}}{8^{15}.10^{22}}=\frac{\left(5^2\right)^{11}.\left(2^2\right)^{33}}{\left(2^3\right)^{15}.\left(2.5\right)^{22}}=\frac{5^{22}.2^{66}}{2^{45}.2^{22}.5^{22}}=\frac{5^{22}.2^{66}}{2^{67}.5^{22}}=\frac{1}{2}\)
b,\(\frac{8^4.5^8.9^3}{125^3.4^7.27}=\frac{\left(2^3\right)^4.5^8.\left(3^2\right)^3}{\left(5^3\right)^3.\left(2^2\right)^7.3^3}=\frac{2^{12}.5^8.3^6}{5^9.2^{14}.3^3}=\frac{3^3}{5.2^2}=\frac{27}{20}\)
Bạn làm nốt nhé cũng tương tự thôi !!!!!!!!!
\(A=18^{15}-\frac{8^5.9^{14}.5}{4^8}.27^{10}-4^7.3^{31}=\left(2.3^2\right)^{15}-\frac{\left(2^3\right)^5.\left(3^2\right)^{14}.5}{\left(2^2\right)^8}.\left(3^3\right)^{10}-\left(2^2\right)^7.3^{31}\)
\(=2^{15}.3^{30}-\frac{2^{15}.3^{28}.5}{2^{16}}.3^{30}-2^{14}.3^{31}\)
\(=2^{15}.3^{30}-\frac{3^{58}.5}{2}-2^{14}.3^{31}\)
\(=2^{14}.3^{30}\left(2-3\right)-\frac{3^{58}.5}{2}=-1.2^{14}.3^{30}-\frac{3^{58}.5}{2}=-1.2^{15}.3^{30}-3^{58}.5\)
\(=3^{30}\left(-1.2^{15}-3^{28}.5\right)\)
410 x 815
= ( 22 ) 10 x ( 23 ) 15
= 22.10 x 23.15
= 220 x 245
= 220 + 45
= 265
\(=\left(2^2\right)^{10}.\left(2^3\right)^{15}=2^{20}.2^{45}=2^{65}\)
ta có : \(2^{30}=\left(2^3\right)^{10}=8^{10}\)
\(3^{20}=\left(3^2\right)^{10}=9^{10}\)
vì \(8< 9\Rightarrow2^{30}< 3^{20}\)
\(4^{15}=\left(4^3\right)^5=64^5\)
\(8^{10}=\left(8^2\right)^5=64^5\)
vì \(64=64\Rightarrow4^{15}=8^{10}\)
2 câu còn lại tương tự
410 : 815 = (22)10 :( 23)15 = 220 : 245 = 2-25