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\(\frac{125}{61}-\frac{22}{39}+\frac{100}{39}-\frac{3}{61}=\left(\frac{125}{61}-\frac{3}{61}\right)+\left(\frac{100}{39}-\frac{22}{39}\right)\)
\(=\frac{122}{61}+\frac{78}{39}=2+2=4\)
\(\frac{4}{6}\)+ y =\(\frac{7}{5}\)
y = \(\frac{7}{5}\)- \(\frac{2}{3}\)
y = \(\frac{21}{15}\)-\(\frac{10}{15}\)
y = \(\frac{11}{15}\)
k cho mk nha
\(\frac{82}{59}+\frac{95}{91}+\frac{36}{59}+\frac{87}{91}=\left(\frac{82}{59}+\frac{36}{59}\right)+\left(\frac{95}{91}+\frac{87}{91}\right)\)
\(=\frac{118}{59}+\frac{182}{91}=2+2=4\)
\(\frac{82}{59}+\frac{95}{91}+\frac{36}{59}+\frac{87}{91}\) \(=\left(\frac{82}{59}+\frac{36}{59}\right)+\left(\frac{95}{91}+\frac{87}{91}\right)=\frac{118}{59}+\frac{182}{92}=2+2=4\)
\(\frac{1}{7}< \frac{x}{13}< \frac{2}{7}\)
\(\frac{1\times13}{7\times13}< \frac{x\times7}{13\times7}< \frac{2\times13}{7\times13}\)
\(\frac{13}{91}< \frac{x7}{91}< \frac{26}{91}\)
\(\Rightarrow13< x7< 26\)
Vì \(x7⋮7\) mà \(13< x7< 26\Rightarrow x7=14;21\)
\(\Rightarrow x=14\div7=2\)
\(x=21\div7=3\)
Ta có:\(\frac{10}{13}<\frac{12}{x}<\frac{10}{12}\)
=>\(\frac{120}{156}<\frac{120}{10x}<\frac{120}{144}\)
=>156>10x>144
=>\(\frac{156}{10}>x>\frac{144}{10}\)
=>15 lớn hơn hoặc bằng x lớn hơn hoặc bằng 14
=>x\(\in\){15,14}
\(\frac{137}{91}-\frac{46}{71}+\frac{117}{71}-\frac{46}{91}\)
\(=\left(\frac{137}{91}-\frac{46}{91}\right)-\left(\frac{46}{71}-\frac{117}{71}\right)\)
\(=\frac{91}{91}-\frac{-71}{71}\)
\(=1-\left(-1\right)=2\)
\(4dm^356cm^3=4.056dm^3\)
\(3m^3500cm^3>3\dfrac{2}{5}m^3\)
\(3.6dm^3=3600cm^3\)
\(40000cm^3=0.04m^3\)
\(\dfrac{100}{30}m^3=\dfrac{100000}{30}dm^3\)