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=>x-(1/5-1/9+1/9-1/13+...+1/41-1/45)=37/45
=>x-8/45=37/45
=>x=1
a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)
= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)
= - 1 + 1 - \(\dfrac{11}{20}\)
= 0 - \(\dfrac{11}{20}\)
= - \(\dfrac{11}{20}\)
b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)
= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)
= \(\dfrac{10}{12}\)
= \(\dfrac{5}{6}\)
c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)
= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)
= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)
= \(\dfrac{14}{3}\)
(-13/31 + -18/31) : 5/17 . 25/34 = -1 . 17/5 . 25/34
= -17/5 . 25/34
= -425/170
= -5/2
Bài 1:
\(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot5^n\)
\(\Leftrightarrow2^n=2\cdot5^n\)
\(\Leftrightarrow2^{n-1}=5^n\)
Bài 2:
a: \(A=\dfrac{2^8+3^8}{2^8}=1+\dfrac{3^8}{2^8}\)
b: \(B=\left(2^{17}+17^2\right)\cdot\left(9^{15}-15^9\right)\cdot\left(16-16\right)=0\)
Lời giải:
$\frac{4}{9}\times \frac{-13}{-17}+\frac{-2}{17}\times \frac{4}{9}+\frac{2}{9}\times \frac{4}{17}$
$=\frac{4}{9}\times (\frac{13}{17}+\frac{-2}{17})+\frac{2}{9}\times \frac{4}{17}$
$=\frac{4}{9}\times \frac{11}{17}+\frac{4}{9}\times \frac{2}{17}$
$=\frac{4}{9}\times (\frac{11}{17}+\frac{2}{17})$
$=\frac{4}{9}\times \frac{13}{17}=\frac{52}{153}$