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=> 1 - (43/8+x-173/24) = 0
=> 43/8 + x - 173/24 = 1
=> 43/8 + x = 197/24
=> x = 17/6
k nha
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=2\)
\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{100}{3}\)
\(\Rightarrow x-\frac{11}{6}=\frac{100}{3}\)
\(\Rightarrow x=\frac{211}{6}\)
a) \(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\Leftrightarrow\frac{11}{15}x=-\frac{2}{5}\Leftrightarrow x=-\frac{6}{11}\)
b) \(\Leftrightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right).-\frac{3}{50}=1\Leftrightarrow\frac{-11}{6}+x=-\frac{50}{3}\Leftrightarrow x=-\frac{37}{2}\)
a/ (3x -12 ):8+10=13
<=>(3x-12):8=3
<=>3x-12=24
<=>3x=36
<=>x=12
b/(x+5)x8-20=60
<=>(x+5)x8=80
<=>x+5=80:8
<=>x+5=10
x=5
c/3x[35+(x-10)]-375=0
<=>3x[35+(x-10)]=375
<=>35+(x+10)=125
<=>x+10=90
x=80
d/(158x+173-24):35=81
<=>158x+173-24=2835
<=>158x+173=2859
<=>158x=2686
<=>x=17
e/x-140:35=0
<=>x-140=0
<=>x=140+0
x=140
\(=>\dfrac{43}{8}+x=-\dfrac{46}{3}+\dfrac{173}{24}=-\dfrac{65}{8}\)
\(=>x=-\dfrac{65}{8}-\dfrac{43}{8}=-\dfrac{27}{2}\)
x=-46/3 +173/24 -43/8
x= 368/24 + 173/24 -129/24
x=103/6