Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{35}{41}.\frac{-25}{21}.\frac{-82}{15}=\frac{50}{9}\)
1, 69. (-74) - 31 . 74
= (-69) . 74 - 31 . 74
= 74(-69 - 31)
= 74(-100)
= -7400
2, (-2020) . 35 - 2020 . 65
= 2020 . (-35) - 2020 . 65
= 2020(-35 - 65)
= 2020(-100)
= -202000
3, -23 . 59 - 159 . 23
= 23 . (-59) - 159 . 23
= 23(-59 - 159)
= 23 . (-218)
= -5014
4, -147 . 47 + (-47)(-47) - 300
= -147 . 47 + 47 . 47 - 300
= 47(-147 + 47) - 300
= 47 . (-100) - 300
= -4700 - 300
= -5000
5, (-72) . 30 - 31 . (-30) + 3 + 30
= (-72) . 30 + 31 . 30 + 3 + 30
= 30(-72 + 31 + 1) + 3
= 30 . (-40) + 3
= -1200 + 3
= -1197
6, (-82)(-55) + (-82) + (-46)(-82)
= (-82)(-55 + 1 - 46)
= (-82)(-100)
= 8200
7, (-41) . 135 + 135 . (-24) - 35 . (-65)
= 135(-41 - 24) - 35(-65)
= 135(-65) - 35(-65)
= (-65)(135 - 35)
= -65(100)
= -6500
10, 125 . (-88)
= 1000 . \(\frac{1}{8}\) . (-88)
= 1000 . (-11)
= -11000
Câu 8 với 9 mình ko hiểu nên ko giúp bn được
Chúc bạn học tốt!
\(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
\(=\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
\(=-1+1-\frac{1}{2}=0-\frac{1}{2}\)
\(=\frac{-1}{2}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(=\left(1\frac{4}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
\(=1+1+0,5=2,5\)
\(\frac{13}{25}+\frac{4}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
= \(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
= \(-1+1-\frac{1}{2}=-\frac{1}{2}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
=\(\left(1\frac{4}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
= \(1+1+0,5=2,5\)
Thế này à:
a, \(\frac{2^{13}+25}{2^{10}}\)
b, \(\frac{21^2.14.125}{35^5.6}\)
c,\(\frac{45^3.20^4.18^2}{180^5}\)
d, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
2 mũ 13 ta chia cho 2 mũ 10 ta có là 2 mũ 3 chuyển thành 8 rồi cộng cho 25 ta có là 33
\(a.\dfrac{2}{3}+\dfrac{1}{5}\cdot\dfrac{10}{7}\\ =\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{20}{21}\\ b.\dfrac{7}{12}-\dfrac{27}{7}\cdot\dfrac{1}{18}\\ =\dfrac{7}{12}-\dfrac{3}{14}=\dfrac{31}{84}\\ c.\left(\dfrac{23}{11}-\dfrac{15}{82}\right)\cdot\dfrac{41}{25}\\ =\dfrac{1721}{902}\cdot\dfrac{41}{25}=\dfrac{1721}{550}\\ d.\left(\dfrac{4}{5}+\dfrac{1}{2}\right)\cdot\left(\dfrac{3}{13}-\dfrac{8}{13}\right)\\ =\dfrac{13}{10}\cdot\left(\dfrac{-5}{13}\right)=\dfrac{-1}{2}\)
\(\frac{35}{41}.\left(-\frac{25}{21}\right).\left(-\frac{82}{15}\right)-\left|5\frac{1}{3}-0,35\right|\)
= \(\frac{35.\left(-25\right).\left(-82\right)}{41.21.15}-\frac{299}{60}\)
= \(\frac{50}{9}-\frac{299}{60}\)
= \(\frac{1000-897}{180}\)= \(\frac{103}{180}\)
\(\frac{35}{41}.-\frac{25}{21}.-\frac{82}{15}-|\frac{51}{3}-0,35|\)
\(=\frac{71750}{12915}-|\frac{51}{3}-\frac{35}{100}|\)
\(=\frac{71750}{12915}-|\frac{5100}{300}-\frac{105}{300}|\)
\(=\frac{71750}{12915}-\frac{4995}{300}\)
\(=...\)
Tự quy đồng rồi rút gọn nhé !!!