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a) 100:{250:[450−(4.53−25.4)]}100:{250:[450−(4.53−25.4)]}
=100:{250:[450−(4.125−25.4)]}=100:{250:[450−(4.125−25.4)]}
=100:{250:[450−(500−100)]}=100:{250:[450−(500−100)]}
=100:[250:(450−400)]=100:[250:(450−400)]
=100:(250:50)=100:(250:50)
=100:5=100:5
=20=20
b) 4(18−15)−(5−3).324(18−15)−(5−3).32
=4.3−2.32=4.3−2.32
=4.3−2.9=4.3−2.9
=12−18=12−18
=−6=−6
a) 12 : { 400 : [500 – (125 + 25 . 7)]}
=12 : { 400 : [500 – (125 + 175)]}
=12 : [ 400 : [500 – 300)]
=12 : (400:200)
=12:2=6
b) 5 . 22 – 18 : 3
=5.4-6
=20-6=14
c) 18 : 3 + 182 + 3.(51 : 17)
=5+182+3.3
=187+9=196
d) 25 . 8 – 12.5 + 170 : 17 – 8
=200-60+10-8
=142
e) 2.52+ 3: 710 – 54: 33
=2.25+3:1-54:27
=50+3-2
=51
f) 189 + 73 + 211 + 127
=(189+211)+(73+127)
=400+200=600
g) 375 : {32 – [ 4 + (5. 32– 42)]} – 14 )
=375 : {32 – [ 4 + (160– 42)]} – 14 )
=375 : [32 – ( 4 + 118) – 14 ]
=375:(32-122-14)
=375:-104
=-375/104
h) (52022 + 52021) : 52021
=(52022:52021)+(52021:52021)
=5+1=6
a) 3^2 . 187 - 87 . 3^2
= 3^2 . ( 187 - 87 )
= 9 . 100
= 900.
b) 4^2 . 19 + 80 . 4^2 + 4^2
= 4^2 . ( 19 + 80 + 1 )
= 16 . 100
= 1600.
c) 73 . 5^2 + 5^2 . 28 - 5^2
= 5^2 . ( 73 + 28 - 1)
= 25 . 100
= 2500
d) 6^2 . 48 + 51 . 6^2 + 36
= 6^2 . 48 + 51 . 6^2 + 6^2
= 6^2 . ( 48 + 51 + 1)
= 36 . 100
= 3600.
e) 113 . 7^2 - 7^2 . 12 - 49
= 113 . 7^2 - 7^2 .12 - 7^2
= 7^2 . ( 113 - 12 - 1 )
= 49 . 100
= 4900.
f) ( 2^3 . 9^4 + 9^3 . 45 ) : ( 9^2 . 10 - 9^2 )
= ( 8 . 3^12 + 3^9 . 3^2 . 5 ) : ( 9^2 . ( 10 - 1 ))
= ( 8 . 3 . 3^11 + 3^11 . 5 ) : ( 9^2 . 9 )
= 3^11 . ( 8 . 3 + 5) : 3^11
= 8 . 3 + 5
= 24 + 5
= 29.
Câu f mik chưa ra cách gọn hơn, bạn thông cảm. :(
a: \(61\cdot45+61\cdot23-68\cdot51\)
\(=61\left(45+23\right)-68\cdot51\)
\(=68\cdot61-68\cdot51\)
\(=68\left(61-51\right)=68\cdot10=680\)
b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)
\(=75-75+4\cdot8\)
\(=4\cdot8=32\)
c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)
\(=\dfrac{36}{20-30+4^2}\)
\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)
d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)
\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)