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a/ 2x + 3x = 1505
\(\Rightarrow\)5x = 1505
\(\Rightarrow\)x = 1505 : 5 = 301
Vậy x = 301
b/ 5x - x = 4088
\(\Rightarrow\)4x = 4088
\(\Rightarrow\)x = 4088 : 4 = 1022
Vậy x = 1022
a) 2x + 3x = 1505
=> 5x = 1505
x = 1505 : 5
x = 301
b) 5x - x = 4088
=> 4x = 4088
x = 4088 : 4
x = 1022
a)\(2x+3x=1505\)
=>\(x\left(2+3\right)=1505\)
=>x.5=1505
=>x=1505:5
=>x=301
b)\(5x-x=4088\)
=>x(5-1)=4088
=>x.4=4088
=>x=4088:4
=>x=1022
a) 2x + 3x = 1505
(2 + 3)x = 1505
5x = 1505
x = 1505 : 5
x = 301
b) 5x - x = 4088
5x - 1x = 4088
(5 - 1)x = 4088
4x = 4088
x = 4088 : 4
x = 1022
a ) \(2x+3x=1505=x\left(2+3\right)=1505=>5x=1505\)
\(=>x=301\)
b ) \(5x-x=4088=>x\left(5-1\right)=4088\)
\(=>4x=4088=>x=1022\)
a) 2x + 3x = 1505
x ( 2 + 3 ) = 1505
x . 5 = 1505
x = 1505 : 5
x = 301
b) 5x - x = 4088
5x - 1x = 4088
( 5 - 1 ) x = 4088
4x = 4088
x = 4088 : 4
x = 1022
5x - x = 4088
( 5 - 1 ) x = 4088
4x = 4088
x = 4088 : 4
x = 1022
1.
a, \(x-14=3x+18\)
\(\Rightarrow x-3x=18+14\)
\(\Rightarrow-2x=32\Rightarrow x=\frac{32}{-2}=-16\)
b, \(\left(x+7\right).\left(x-9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+7=0\\x-9=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-7\\x=9\end{cases}}}\)
c, \(\left|2x-5\right|-7=22\)
\(\Rightarrow\left|2x-5\right|=22+7\)
\(\Rightarrow\left|2x-5\right|=29\)
\(\Rightarrow\orbr{\begin{cases}2x+5=29\\2x-5=29\end{cases}}\Rightarrow\orbr{\begin{cases}2x=24\\2x=34\end{cases}\Rightarrow}\orbr{\begin{cases}x=12\\x=17\end{cases}}\)
d, \(\left(\left|2x\right|-5\right)-7=22\)
\(\Rightarrow\left(\left|2x\right|-5\right)=29\)
\(\Rightarrow\left|2x\right|=29+5\Rightarrow\left|2x\right|=34\Rightarrow x=\pm17\)
e, \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\)
Vì \(\left|x+3\right|\ge0;\left|x+9\right|\ge0;\left|x+5\right|\ge0;4x\ge0\)
Nên \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\ge0\)
\(\Rightarrow\left|x+3\right|>0\Rightarrow\left|x+3\right|=x+3\)
\(\left|x+9\right|>0\Rightarrow\left|x+9\right|=x+9\)
\(\left|x+5\right|>0\Rightarrow\left|x+5\right|=x+5\)
Ta có :
\(x+3+x+9+x+5=4x\)
\(\Rightarrow3x+\left(3+9+5\right)=4x\)
\(\Rightarrow4x-3x=17\)
\(\Rightarrow x=17\)
2. a , b sai đề bn
c, \(\left(5x+1\right).\left(y-1\right)=4\)
\(\Rightarrow\left(5x+1\right).\left(y-1\right)\inƯ\left(4\right)\)
\(\text{ }Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)
Ta có bảng sau :
5x+1 | 1 | -1 | 2 | -2 | 4 | -4 |
y-1 | -4 | 4 | -2 | 2 | -1 | 1 |
x | 0 | -2/5 | 1/5 | -3/5 | 3/5 | -1 |
y | -3 | 5 | -1 | 3 | 0 | 2 |
d, \(5xy-5x+y=5\)
\(\Rightarrow\left(5xy-5x\right)+y=5\)
\(\Rightarrow5x.\left(y-1\right)+y=5\)
\(\Rightarrow\left(5x+1\right).\left(y-1\right)=4\)
\(\Rightarrow\left(5x+1\right).\left(y-1\right)\inƯ\left(4\right)\)
\(Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)
Ta có bảng sau :
5x+1 | 1 | -1 | 2 | -2 | 4 | -4 |
y-1 | -4 | 4 | -2 | 2 | -1 | 1 |
x | 0 | -2 | 1/5 | -3/5 | 3/5 | -1 |
y | -3 | 5 | -1 | 3 | 0 | 2 |
\(a,2x+15=27\)
\(\Rightarrow2x=27-15\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=12\div2\)
\(\Rightarrow x=6\)