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\(2^8\cdot x-415=7^4\)
\(\Leftrightarrow256x-415=2401\)
\(\Leftrightarrow256x=2401+415\)
\(\Leftrightarrow256x=2816\)
\(\Leftrightarrow x=2816:256\)
\(\Leftrightarrow x=11\)
b, 2x = 42x45 /8
2x = 16x45 /8
2x = 2x45
2x = 2x(22)5
2x = 2x210
2x = 211
=> x = 11
\(\left(3.x-2^4\right).7^3=2.8^4\)
\(\Leftrightarrow\left(3.x-16\right).343=2.4096\)
\(\Leftrightarrow\left(3.x-16\right).343=8192\)
\(\Leftrightarrow3.x-16=8192:343\)
\(\Leftrightarrow3.x-16=\frac{8192}{343}\)
\(\Leftrightarrow3.x=\frac{8192}{343}+16\)
\(\Leftrightarrow3.x=\frac{13680}{343}\)
\(\Leftrightarrow x=\frac{13680}{343}:3\)
\(\Leftrightarrow x=\frac{4560}{343}\)
(3.x-2^4).7^3=2.8^4
(3.x-16).343=2.4096
(3.x-16).343=8192
3.x-16 =8192:343
3.x-16 =23,88
3.x =23+16
3.x =39
x =39:3
x=13
1,
-8.3 - 9:9 + 25 = 0
2,
x= 3
y= -10
x-y= 3+10 =13
3,
-415+ 34 - 83 - 34 + 415 - 37 = 120
a, \(\Leftrightarrow\)\(2x=-32\)
\(\Leftrightarrow\)\(x=-16\)
b,\(\Leftrightarrow\)\(25-\left(5x-3\right)=64\)
\(\Leftrightarrow\)\(5x-3=-39\)
\(\Leftrightarrow\)\(5x=-36\)
\(\Leftrightarrow\)\(x=-7,2\)
c,\(\Leftrightarrow\)\(25-\left(x-5\right)=15\)
\(\Leftrightarrow\)\(x-5=10\)
\(\Leftrightarrow\)\(x=15\)
Ta có " (x - 5)7 = (x - 5)4
=> (x - 5)7 - (x - 5)4 = 0
<=> (x - 5)4[(x - 5)3 - 1] = 0
\(\Leftrightarrow\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^3-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\\left(x-5\right)^3=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x-5=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}\)