Question

[Nguyễn Thanh Thúy]

2^91 và 5^36

Answer 1

[HT.Phong (9A5)]

\(2^{91}>2^{90}\)

Ta có:

\(2^{90}=\left(2^5\right)^{18}=32^{18}\)

\(5^{36}=\left(5^2\right)^{18}=25^{18}\)

Mà: \(32>25\)

\(\Rightarrow32^{18}>25^{18}\)

\(\Rightarrow2^{90}>5^{36}\)

\(\Rightarrow2^{91}>5^{36}\)

Answer 2

[Võ Ngọc Phương]

Ta có:

\(2^{91}>2^{90}=\left(2^5\right)^{18}=32^{18}>25^{18}=\left(5^2\right)^{18}=5^{2.18}=5^{36}\)

Vậy \(2^{91}>5^{36}\).