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\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
[199-(x-6)]= 2448:24
[199-(x-6)] =102
x-6= 199-102
x-6=97
x=97+6
x=103
a <=>12x-4^3=32
<=>12x=96
<=>x=8
b, <=>3x-6=27
<=>3x=33
<=>x=11
c, <=>119-(x-6)=102
<=>x-6=17
<=>x=23
hok tot
a) ( 12x - 43 ) . 83 = 4.84
=> ( 12x - 43 ) : 4 = 84 : 83
=> ( 12x - 43 ) : 4 = 8
=> 12x - 43 = 8 . 4
=> 12x - 64 = 32
=> 12x = 96
=> x = 8
b) ( 3x - 6 ) . 3 = 34
=> ( 3x - 6 ) = 34 : 31
=> 3x - 6 = 33
=> 3x - 6 = 27
=> 3x = 33
=> x = 11
c) 2448 : [ 119 - ( x - 6 ) ] = 24
=> 119 - ( x - 6 ) = 102
=> x - 6 = 7
=> x = 13
a, => x-1=0 => x=1
b, => 2^3.x-7 = 7^12:7^10 = 7^2=49
=> 8.x=49+7=56
=> x=56:8=7
c,=>5^33:x=5^31
=> x=5^33 : 5^31 = 5^2 = 25
d, => 119-(x-6) = 2448 : 24 = 102
=> x-6 = 119-102 = 17
=> x=17+6=23
k mk nha
anh Nguyễn Anh Quân ơi câu a phải là (1;-1) chứ vì là giá trị tuyệt đối mà
1 . 3.2x - 3 = 45
3.2x=45+3
3.2x=48
2x=48:3
2x=16
2x=24
vậy=4
2 . 2448 : [ 119 - ( x - 6 ) ] = 0
119 - ( x - 6 ) = 2448:0
119 - ( x - 6 ) = 0
x-6=0+119
x-6=199
x=199+6
x= 205
3. 4x3 + 12 = 120
4x3 =120-12
4x3 = 108
x3=108:4
x3=27
x3=33
vẫy=3
a) \(128-3\left(x+4\right)=23\)
\(\Rightarrow3\left(x+4\right)=128-23\)
\(\Rightarrow3\left(x+4\right)=105\)
\(\Rightarrow x+4=105:3\)
\(\Rightarrow x+4=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
Vậy x = 31
b) \(\left(6x-3^3\right).5^3=3.5^4\)
\(\Rightarrow6x-27=3.5^4:5^3\)
\(\Rightarrow6x-27=15\)
\(\Rightarrow6x=15+27\)
\(\Rightarrow6x=42\)
\(\Rightarrow x=42:6\)
\(\Rightarrow x=7\)
Vậy x = 7
c) \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Rightarrow119-\left(x-6\right)=2448:24=102\)
\(\Rightarrow x-6=119-102=17\)
\(\Rightarrow x=17+6=23\)
Vậy x = 23
d) \(130-\left[5.\left(9-x\right)+43\right]=47\)
\(\Rightarrow5.\left(9-x\right)+43=130-47=83\)
\(\Rightarrow5.\left(9-x\right)=83-43=40\)
\(\Rightarrow9-x=40:5=8\)
\(\Rightarrow x=9-8=1\)
Vậy x = 1
128 - 3( x+4 ) = 23
=> 3 (x+4) = 128 -23
=> 3(x+4) = 105
=> x+4 = 105 / 3
=> x+4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31
Bài 1: Thực hiện phép tính
a) 165 - [ 120 - ( 9 - 4 )2 ]
b) 32 : { 160 : [ 300 - ( 175 + 21 . 5 ) ] }
c) 6 . 52 - 32 : 24 + 32
d) 42 .37 - 42 . 33 + 24
Bài làm:
a) 165 - [ 120 - ( 9 - 4 )2 ]
= 165 - [ 120 - 52 ]
= 165 - [ 120 - 25 ]
= 165 - 95
= 70.
b) 32 : { 160 : [ 300 - ( 175 + 21 . 5 ) ] }
= 32 : { 160 : [ 300 - ( 175 + 105) ] }
= 32 : { 160 : [ 300 - 280 ] }
= 32 : { 160 : 20 }
= 32 : 8
= 4.
c) 6 . 52 - 32 : 24 + 32
= 6 . 25 - 32 : 16 + 9
= 150 - 2 + 9
= 148 + 9
= 157.
d) 42 .37 - 42 . 33 + 24
= 16. ( 37 - 33)
= 16 . 4
= 64.
Bài 2: Tìm số tự nhiên x, biết:
a) 91-5 . ( 5 + x ) = 61
b) ( x + 34 ) - 40 = 28
c) 3 . ( x -2 ) + 150 = 240
d) 360 : ( x- 7) = 90
e) 2448 : [ 119 - ( x - 6) ] = 24.
Bài làm:
a) 91-5 . ( 5 + x ) = 61
5 . ( 5 + x) = 91 - 61
5. ( 5+ x) = 30
5 +x = 30 : 5
5 +x = 6
x = 6 - 5
x = 1.
b) ( x + 34 ) - 40 = 28
x+ 34 = 40 + 28
x+ 34 = 68
x = 68 - 34
x = 34.
c) 3 . ( x - 2 ) + 150 = 240
3 . ( x - 2 ) = 240 - 150
3 . ( x - 2 ) = 90
x - 2 = 90 : 3
x - 2 = 30
x = 30 + 2
x = 32.
d) 360 : ( x - 7 ) = 90
x - 7 = 360 : 90
x - 7 = 4
x = 4 + 7
x = 11.
e) 2448 : [ 119 - ( x - 6 ) ] = 24
[ 119 - ( x - 6 ) ] = 2448 : 24
[ 119 - ( x - 6 ) ] = 102
x - 6 = 119 + 102
x - 6 = 221
x = 221 + 6
x = 227.
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2448 : [199 - (x - 6)] = 24
199 - (x -6 ) = 2448 : 24 =102
x - 6 = 199 - 102 = 97
x = 97 + 6
x = 103
\(3^{x+1}=27\)
\(\Rightarrow3^x.3=27\)
\(\Rightarrow3^x=27:3=9=3^2\)
\(\Rightarrow x=2\)