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a) \(1,2:3,36=\dfrac{6}{5}:\dfrac{84}{25}=\dfrac{5}{14}\)
b)\(3\dfrac{1}{7}:2\dfrac{5}{14}=\dfrac{22}{7}:\dfrac{33}{14}=\dfrac{4}{3}\)
c)\(\dfrac{3}{8}:0,54=\dfrac{3}{8}:\dfrac{27}{50}=\dfrac{25}{36}\)
a)\(1,5:2,16=15:216=5:72\)
b)\(4\dfrac{2}{7}:\dfrac{3}{5}=\dfrac{30}{7}:\dfrac{3}{5}=\dfrac{30}{7}.\dfrac{5}{3}=\dfrac{50}{7}=50:7\)
c)\(\dfrac{\dfrac{2}{9}}{0,31}=\dfrac{2}{9}:\dfrac{31}{100}=\dfrac{2}{9}.\dfrac{100}{31}=\dfrac{31}{450}=31:450\)
a) \(2.04:\left(-3.12\right)=\dfrac{204}{-312}=\dfrac{-17}{26}\)
b) \(\left(-1\dfrac{1}{2}\right):1.25=\dfrac{-3}{2}:\dfrac{5}{4}=\dfrac{-3}{2}\cdot\dfrac{4}{5}=\dfrac{-12}{10}=\dfrac{-6}{5}\)
c) \(4:5\dfrac{3}{4}=4:\dfrac{23}{4}=4\cdot\dfrac{4}{23}=\dfrac{16}{23}\)
d) \(10\dfrac{3}{7}:5\dfrac{3}{14}=\dfrac{73}{7}:\dfrac{73}{14}=\dfrac{2}{1}\)
a, Ta có : \(1,2=\dfrac{12}{10}=\dfrac{6}{5}\) ; \(3,36=\dfrac{84}{25}\)
=> \(1,2:3,36=\dfrac{6}{5}:\dfrac{84}{25}=\dfrac{5}{14}\)
b, Ta có : \(3\dfrac{1}{7}:2\dfrac{5}{14}=\dfrac{22}{7}:\dfrac{33}{14}=\dfrac{4}{3}\)
c,\(\dfrac{3}{8}:0,54=\dfrac{3}{8}:\dfrac{27}{50}=\dfrac{25}{36}\)