Câu hỏi của Nguyễn Hoàng Vũ

Question

1.viết tích sau dưới dạng 1 lũy thừa

$7^2\cdot49^3\cdot7^7$

$3^5\cdot9^4\cdot27^2\cdot81$

Mashiro Shiina · Accepted Answer

$7^2.49^3.7^7=7^2.\left(7^2\right)^3.7^7=7^2.7^6.7^7=7^{15}$

$3^5.9^4.27^2.81=3^5.\left(3^2\right)^4.\left(3^3\right)^2.3^4=3^5.3^8.3^6.3^4=3^{23}$

Câu trả lời:

$7^2.49^3.7^7=7^2.\left(7^2\right)^3.7^7=7^2.7^6.7^7=7^{15}$

$3^5.9^4.27^2.81=3^5.\left(3^2\right)^4.\left(3^3\right)^2.3^4=3^5.3^8.3^6.3^4=3^{23}$

Kudo Shinichi · Answer

a) $7^2.49^3.7^7=7^2.7^6.7^7=7^{15}$

b) $3^5.9^4.27^2.81=3^5.3^8.3^6.3^4=3^{23}$

Câu trả lời:

a) $7^2.49^3.7^7=7^2.7^6.7^7=7^{15}$

b) $3^5.9^4.27^2.81=3^5.3^8.3^6.3^4=3^{23}$