Question

[bùi thị trà my]

1.tính trị của các biểu thức sau

a. A= 3/4-{5/2+5/3} +{-1/3}²

b.B= -11/19 ✖ 4/13 + (-11)/13 ✖ 15/19+11/13

Answer 1

[Ngô Đức Phong]

\(A=\frac{3}{4}-\left(\frac{5}{2}+\frac{5}{3}\right)+\left(\frac{-1}{3}\right)^2\)

\(\Rightarrow A=\frac{3}{4}-\left(\frac{15}{6}+\frac{10}{6}\right)+\frac{1}{9}\)

\(\Rightarrow A=\frac{3}{4}-\frac{25}{6}+\frac{1}{9}\)

\(\Rightarrow A=\frac{18}{24}-\frac{100}{24}+\frac{1}{9}\)

\(\Rightarrow A=\frac{-82}{24}+\frac{1}{9}\)

\(\Rightarrow A=\frac{-41}{12}+\frac{1}{9}=\frac{-123}{36}+\frac{4}{36}=\frac{-119}{36}\)

Vậy A=\(\frac{-119}{36}\)

b)\(B=\frac{-11}{19}.\frac{4}{13}+\frac{-11}{13}.\frac{15}{19}+\frac{11}{13}\)

\(\Rightarrow B=\frac{-11}{19}.\frac{4}{13}+\frac{11}{13}.\left(\frac{-15}{19}+1\right)\)

\(\Rightarrow B=\frac{-11}{19}.\frac{4}{13}+\frac{11}{13}.\frac{4}{19}\)

\(\Rightarrow B=\frac{-11}{13}.\frac{4}{19}+\frac{11}{13}.\frac{4}{19}=\frac{4}{19}.\left(\frac{-11}{13}+\frac{11}{13}\right)=\frac{4}{19}.\frac{0}{13}=\frac{4}{19}.0=0\)

Vậy B=0

Chúc bn học tốt