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\(\dfrac{48}{25}\cdot\dfrac{27}{55}+2\dfrac{4}{9}\cdot\dfrac{14}{33}\)
\(=\dfrac{1296}{1375}+\dfrac{22}{9}\cdot\dfrac{14}{33}\\ =\dfrac{1296}{1375}+\dfrac{28}{27}\\ =\dfrac{34992}{37125}+\dfrac{38500}{37125}\\ =\dfrac{73492}{37125}\)
\(1\dfrac{19}{22}\cdot\left(\dfrac{47}{77}-\dfrac{16}{15}\right)\\ =\dfrac{41}{22}\cdot\dfrac{-527}{1155}\\ =\dfrac{-21607}{25410}\)
\(\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right)-\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\\ =\left(\dfrac{307}{99}+\dfrac{37}{99}-\dfrac{1503}{299}\right)-0\\ =\dfrac{344}{99}-\dfrac{1053}{299}\\ =-\dfrac{107}{2277}\)
a, Ta có : \(7^6+7^5-7^4\)
\(=7^4.7^2+7^4.7+7^4.1=7^4.49+7^4.7+7^4.1\)
\(=7^4.\left(49+7-1\right)\)
\(=7^4.55\) \(⋮\) \(55\) (vì \(55⋮55\))
Vậy \(7^6+7^5-7^4⋮55\)
b, Ta có : \(3^{n+2}-2^{n+2}+3^n-2^n\)
\(=3^n.3^2-2^n.2^2+3^n-2^n\)
\(=\left(3^n.3^2+3^n\right)-\left(2^n.2^2+2^n\right)\)
\(=3^n.\left(3^2+1\right)-2^n.\left(2^2+1\right)\)
\(=3^n.\left(9+1\right)-2^n.\left(4+1\right)\)
\(=3^n.10-2^n.5\)
\(=3^n.2.5-2^{n-1}.2.5\)
\(=2.5.\left(3^n-2^{n-1}\right)\) chia hết cho 2 và 5( vì \(2⋮2\) ; \(5⋮5\) )
Vậy \(3^{n+2}-2^{n+2}+3^n-2^n\) chia hết cho 2 và 5
\(\left[\dfrac{4}{9}+\left(\dfrac{3}{8}x.\left(-\dfrac{1}{2}\right)\right)\right].\dfrac{6}{11}=\dfrac{18}{55}\)
\(\Rightarrow\)\(\left[\dfrac{4}{9}+\left(\dfrac{3}{8}x.\left(-\dfrac{1}{2}\right)\right)\right]=\dfrac{18}{55}:\dfrac{6}{11}\)
\(\Rightarrow\dfrac{4}{9}+\dfrac{3}{8}x.\dfrac{-1}{2}=\dfrac{3}{5}\)
\(\Rightarrow\dfrac{3}{8}x.\dfrac{-1}{2}=\dfrac{3}{5}-\dfrac{4}{9}\)
\(\Rightarrow\dfrac{3}{8}x.\dfrac{-1}{2}=\dfrac{7}{45}\)
\(\Rightarrow\dfrac{3}{8}x=\dfrac{7}{45}:\dfrac{-1}{2}\)
\(\Rightarrow\dfrac{3}{8}x=\dfrac{-14}{45}\)
\(\Rightarrow x=\dfrac{-112}{135}\)
a) 100x +101.50 = 5950
100 x = 900
x = 9
b) (1.2 + 1.2.3.4) . x = 26
26 .x = 26
x =1
2) 11a + 11b = 55
a+b =5 = 1+4 = 2+3
ab = 14;41;23;32.
a,Ta có: (x + 1) + (x + 2) + (x + 3) +....+ ( x + 100) = 5950
=> (x + x + x + .... + x) + (1 + 2 + 3 + .... + 100) = 5950
=> 100x + 5050 = 5950
=> 100x = 5950 - 5050
=> 100x = 900
=> x = 900 : 100
=> x = 9