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Bài 1:
A,
(100+121+144)÷(169+196)
=365:365=1
B
,1.2.3...7.8.(9-1-8)
=1.2.3...7.8.0=0
C,
3^2.2^4.2^32/11.2^13.2^22-2^26
=3^2.2^36/11.2^35-2^36
=3^2.2^36/2^35-(11-2)
=9.2/9=2
D,
=1152-374-1152+(-65)+374
=(1152-1152)+(-374+374)+(-65)
=0+0+(-65)=-65
E,
=13-(12-11-10+9)+(8-7-6+5)-(4-3-2+1)
=13-0+0-0=13
Bài 2:
A,(19x+50)÷14=25-16
(19x+50)÷14=9
19x+50=126
19x=76
x=4
B,
31x+(1+2+3+...+30)=1240
31x+465=1240
31x=775
×=25
1, 4\(^{x+1}\) + 4\(^0\) = 65
\(\Rightarrow\)4\(^{x+1}\) = 65 - 1
\(\Rightarrow\)x + 1 = 64 : 4
\(\Rightarrow\)x + 1 = 16
\(\Rightarrow\)x = 15
2) 10 + 2x = 16\(^{^2}\): 4\(^3\)
\(\Rightarrow\)10 + 2x = 4
\(\Rightarrow\)2x = 4 - 10
\(\Rightarrow\)2x = -6
\(\Rightarrow\)x = -3
1)=>3(x-5)(2x+9)+3(x-5)=0=>(x-5)(6x+30)
=>x-5=0=>x=5
6x+30=0=>x=-5
2)=>x^2-16=0=>x=+-4
12-4x=0=>x=3
3)=>9-x^2=0=>x=+-3
4x-8=0=>x=2
4)=>8-x^3=0=>x=3
5^x-125=0=>x=2
5)=>2^x.2^x=8=>2^2x=8=>2x=3=>x=1,5
b, 2x = 42x45 /8
2x = 16x45 /8
2x = 2x45
2x = 2x(22)5
2x = 2x210
2x = 211
=> x = 11
Tìm x\(\in\)n
a,x3-23=25-(316:314+28:216)
b,5x-2-32=24-(68:66-62)
c,(x2-1)4=81
d,3x+42=196:(193.192)-3.1
Lời giải:
$=65\times 8^2:(4^3\times 2^5)=65\times (2^3)^2:[(2^2)^3\times 2^5]$
$=65\times 2^6:(2^6\times 2^5)=65:2^5=\frac{65}{32}$
\(16.65.8^2:\left(4^3.2^5.16\right)=2^4.65.2^6:\left(2^6.2^5.2^4\right)\)
\(=\dfrac{65}{2^5}=\dfrac{65}{32}\)