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\(\frac{\left(15\cdot x+364\right)}{x}=41\)
\(15\cdot x+364=41\cdot x\)
\(41\cdot x-15\cdot x=364\)
\(26\cdot x=364\)
\(x=\frac{364}{26}\)
\(x=14\)
Bài làm:
Ta có: \(3\cdot\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{15}\)
\(\Leftrightarrow3x\cdot\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}\right)=4\)
\(\Leftrightarrow x\cdot\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}\right)=4\)
\(\Leftrightarrow x\cdot\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=4\)
\(\Leftrightarrow x\cdot\left(1-\frac{1}{13}\right)=4\)
\(\Leftrightarrow x\cdot\frac{12}{13}=4\)
\(\Rightarrow x=\frac{13}{3}\)
Ta có : \(3\times\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{15}\)
=> \(3\times x\times\left(\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+\frac{1}{130}\right)=4\)
=> \(x\times\left(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}\right)=4\)
=> \(x\times\left(\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}\right)=4\)
=> \(x\times\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=4\)
=> \(x\times\left(1-\frac{1}{13}\right)=4\)
=> \(x\times\frac{12}{13}=4\)
=> \(x=4:\frac{12}{13}\)
=> \(x=\frac{13}{3}\)
364 + 364 + 364 + 364 + 364 + 364 + 364 + 364 + 364 + 364
= 364 x 10
= 3600
<=> \(\frac{15a+364}{a}=41\Leftrightarrow15a+364=41a\Leftrightarrow26a=364\Rightarrow a=14\)
Tìm x :
x - 225 : 25 = 15
x - 9 = 15
x = 15 + 9
x = 24