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1. Tìm x:
a) 135 - 3 x ( x- 1) = 3^4 + 6^2
x=-2, x=3
b) 3 x ( x + 7 ) = 5^2 + 5
x=-căn bậc hai(89)/2-7/2, x=căn bậc hai(89)/2-7/2
2. So sánh 2^20 và 3^15
2 ^20 < 3 ^15
1) \(2^{x+1}\cdot2^{2014}=2^{2015}\)\(\Leftrightarrow2^{2014x+2014}=2^{2015}\)\(\Leftrightarrow2014x+2014=2015\)\(\Leftrightarrow x=\frac{1}{2014}\)
2) \(7x-2x=\frac{6^{17}}{6^{15}}+\frac{44}{11}\)\(\Leftrightarrow5x=6^2+4=36+4=40\)\(\Leftrightarrow x=\frac{40}{5}=8\)
3) \(3^x=9\)\(\Leftrightarrow3^x=3^2\)\(\Leftrightarrow x=2\)
4) \(7x-x=\frac{5^{21}}{5^{19}}+3\cdot2^2-7^0\)\(\Leftrightarrow6x=5^2+3\cdot4-1=25+12-1=36\)\(\Leftrightarrow x=6\)
5) \(4^x=64\)\(\Leftrightarrow4^x=4^3\)\(\Leftrightarrow x=3\)
6) \(9^{x-1}=9\)\(\Leftrightarrow x-1=1\)\(\Leftrightarrow x=0\)
7) \(\frac{2^x}{2^5}=1\)\(\Leftrightarrow2^{x-5}=2^0\)\(\Leftrightarrow x-5=0\)\(\Leftrightarrow x=5\)
8) \(\left(5x-9\right)^3=216\)\(\Leftrightarrow\left(5x-9\right)^3=6^3\)\(\Leftrightarrow5x-9=6\)\(\Leftrightarrow5x=15\)\(\Leftrightarrow x=3\)
9) \(5\cdot3^{7x-11}=135\)\(\Leftrightarrow5.3^{7x-11}=5.3^3\)\(\Leftrightarrow3^{7x-11}=3^3\)\(\Leftrightarrow7x-11=3\)\(\Leftrightarrow7x=14\Leftrightarrow x=2\)
10) \(2.3^x=19\cdot3^8-81^2\)\(\Leftrightarrow2.3^x=19\cdot3^8-3^8=18.3^8=2.3^{11}\)\(\Leftrightarrow3^x=3^{11}\Leftrightarrow x=11\)
Đây là cách làm của mình. Bạn có thể chỉnh sửa tuỳ ý theo cách làm của bạn nhé ^^
Học tốt ^3^
a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
a) \(\left(2x+7\right)+135=0\)
\(\Rightarrow2x+7=-135\)
\(\Rightarrow2x=-135-7\)
\(\Rightarrow2x=-142\)
\(\Rightarrow x=-142:2\)
\(\Rightarrow x=-71\)
Vậy x = -71
b) \(\left(-2\right)^4+\left(x-3\right)=\left(15-79\right)^0\)
\(\Rightarrow16+\left(x-3\right)=\left(-64\right)^0\)
\(\Rightarrow16+\left(x-3\right)=1\)
\(\Rightarrow x-3=1-16\)
\(\Rightarrow x-3=-15\)
\(\Rightarrow x=-15+3\)
\(\Rightarrow x=-12\)
Vậy x = -12
c) \(\left(2x-1\right)-3^2=4^3\)
\(\Rightarrow\left(2x-1\right)-9=64\)
\(\Rightarrow2x-1=64+9\)
\(\Rightarrow2x-1=73\)
\(\Rightarrow2x=73+1\)
\(\Rightarrow2x=74\)
\(\Rightarrow x=74:2\)
\(\Rightarrow x=37\)
Vậy x = 37
_Chúc bạn học tốt_
a) (2x+7)+135=0
2x + 7 = -135
2x = -135-7
2x = -142
x = -71
b) (-2)4+(x-3)=(15-79)0
16 + (x-3) = 1
16 + x - 3 = 1
16-3 +x = 1
13 + x = 1
x = -12
c) (2x-1) - 32=43
(2x-1) - 9 = 64
2x - 1 - 9 = 64
2x - 10 = 64
2x = 74
x = 37
a) \(3^{x+1}.15=135\)
\(\Rightarrow3^{x+1}=9\)
\(\Rightarrow3^{x+1}=3^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
b) \(x+2x+2^2x+....+2^{2016}x=2^{2017}-1\\ \Rightarrow x\left(2+2^2+...+2^{2016}\right)=2^{2017}-1\\ \Rightarrow x\left(2^{2017}-2\right)=2^{2017}-1\)
c) \(x\left(x-1\right)+\left(x-1\right)^2=0\\ \Rightarrow x\left(x-1\right)+\left(x-1\right)\left(x-1\right)=0\\ \Rightarrow\left(x-1\right)\left(x+\left(x-1\right)\right)=0\\ \Rightarrow\left(x-1\right)\left(2x-1\right)=0\\ \Rightarrow\begin{cases}x-1=0\\2x-1=0\end{cases}\)
d) \(2^2.2^5\le2^{x-5}\le2^{10}\\ \Rightarrow2^7\le2^{x-5}\le2^{10}\)
Câu 2:
a: \(=\left(-2\right)^3\cdot\left(-3\right)^3\cdot5^3=30^3\)
b: \(=3^3\cdot\left(-2\right)^3\cdot\left(-7\right)\cdot\left(-7\right)^2\)
\(=\left(3\cdot2\cdot7\right)^3=42^3\)
135-x=15
x=135 - 15
x=120
Vậu x = 120
4.x=75.4-4.72
4.x=4.(75-72)
4.x=4.3
=> x= 3
Vậy x = 3
5.x-3=23.32
5.x-3=8.9
5.x-3=72
5.x=72+3
5.x=75
x=75:5
x=15
Vậy x = 15
a) x=135-15
x=120