Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1) x2- 3x - 6x +18
= (x2- 3x )-(6x -18 )
= x(x-3)- 6(x-3)
= (x-6)(x-3)
Bài làm:
Ta có: \(4x^4-12x^2+1\)
\(=4\left(x^4-3x^2+\frac{9}{4}\right)-8\)
\(=4\left(x^2-\frac{3}{2}\right)^2-\left(\sqrt{8}\right)^2\)
\(=\left[2\left(x^2-\frac{3}{2}\right)-2\sqrt{2}\right]\left[2\left(x^2-\frac{3}{2}\right)+2\sqrt{2}\right]\)
\(=4\left(x^2-\frac{3+2\sqrt{2}}{2}\right)\left(x^2-\frac{3-2\sqrt{2}}{2}\right)\)
\(=4\left(x-\sqrt{\frac{3+2\sqrt{2}}{2}}\right)\left(x+\sqrt{\frac{3+2\sqrt{2}}{2}}\right)\left(x-\sqrt{\frac{3-2\sqrt{2}}{2}}\right)\left(x+\sqrt{\frac{3-2\sqrt{2}}{2}}\right)\)
Hình như đề bài hơi sai sai í bn '^' Mk nghĩ sửa 12x thành 12xy nha
TL :
4x2 - 12xy + 5y2
= 4x2 - 2xy - 10xy + 5y2
= 2x( 2x - y) - 5y( 2x - y )
= ( 2x - 5y )( 2x - y )
Thế này là xog òi đó bn :)
Nếu đề bài là đúng như bn vt trên kia thỳ xl ạ :>
Mk k phân tích đc :)
Đồng ý với bạn Linh nhé :3
4x2 - 12xy + 5y2
= 4x2 - 2xy - 10xy + 5y2
= 2x( 2x - y) - 5y( 2x - y)
= ( 2x - y)(2x - 5y )
Mk nghĩ như v ms đúng :)
\(x^4-4x^3+9x^2-10x+6\)
\(=x^4-2x^3+3x^2-2x^3+4x^2-6x+2x^2-4x+6\)
\(=x^2\left(x^2-2x+3\right)-2x\left(x^2-2x+3\right)+2\left(x^2-2x+3\right)\)
\(=\left(x^2-2x+3\right)\left(x^2-2x+2\right)\)
\(12x^2+7x-12\)
\(=12x^2-9x+16x-12\)
\(=3x\left(4x-3\right)+4\left(4x-3\right)\)
\(=\left(4x-3\right)\left(3x+4\right)\)
12x^2+7x-12=(12x^2-9x)+(16x-12)=3x(4x-3)+4(4x-3)=(3x+4)(4x-3)
chúc hok tốt
10x2 + 17x - 6
\(=10x^2+20x-3x-6\)
\(=10x\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(10x-3\right)\)
- 10x2 - 17x +6
\(=-10x^2-20x+3x+6\)
\(=-10x\left(x+2\right)+3\left(x+2\right)=\left(x+2\right)\left(-10x+3\right)\)
- 10x2 + 28x + 6
\(=-10x^2+30x-2x+6\)
\(=-10x\left(x+3\right)-2\left(x+3\right)=-\left(x+3\right)\left(10x+2\right)\)
10x2 - 28x -6
\(=10x^2-30x+2x-6\)
\(=10x\left(x-3\right)+2\left(x-3\right)=\left(x-3\right)\left(10x+2\right)\)
1) \(6x^2-15x+6\)
\(=6x^2-3x-12x+6\)
\(=3x\left(2x-1\right)-6\left(2x-1\right)\)
\(=\left(3x-6\right)\left(2x-1\right)\)
\(=3\left(x-2\right)\left(2x-1\right)\)
b) \(6x^2-20x+6\)
\(=6x^2-2x-18x+6\)
\(=2x\left(3x-1\right)-6\left(3x-1\right)\)
\(=\left(2x-6\right)\left(3x-1\right)\)
\(=2\left(x-3\right)\left(3x-1\right)\)
c) \(-10x^2-7x+6\)
\(=5x-10x^2+6-12x\)
\(=5x\left(1-2x\right)+6\left(1-2x\right)\)
\(=\left(5x+6\right)\left(1-2x\right)\)
d) \(10x^2-7x-12\)
\(=10x^2-15x+8x-12\)
\(=5x\left(2x-3\right)+4\left(2x-3\right)\)
\(=\left(5x+4\right)\left(2x-3\right)\)
1) 6x^2 - 15x + 6
= 6x^2 - 12x - 3x +6
= 6x (x - 2) - 3 (x - 2)
= (x - 2) (6x - 3)
= 3 (x - 2) (x - 1)
2) 6x^2 - 20x + 6
= 6x^2 - 18x - 2x + 6
= 6x (x - 3) - 2 (x - 3)
= (x - 3) (6x - 2)
= 2 (x - 3) (3x - 1)
3) -10x^2 - 7x + 6
= -10x^2 + 5x - 12x + 6
= 5x (1 - 2x) + 6 (1 - 2x)
= (1 - 2x) (5x + 6)
4) 10x^2 - 7x - 12
= 10x^2 - 15x + 8x - 12
= 5x (2x - 3) + 4 (2x - 3)
= (2x - 3) (5x + 4)
good luck !
12x2 + 7x - 12
= 12x2 + 16x - 9x - 12
= 4x.( 3x + 4 ) - 3.( 3x + 4 )
= ( 3x + 4 ).( 4x - 3 )
\(12x^2+7x-12\)
\(=12x^2+16x-9x-12\)
\(=4x\left(3x+4\right)-3\left(3x+4\right)\)
\(=\left(4x-3\right)\left(3x+4\right)\)