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\(107-\left\{38+\left[7.3^2-24:6+\left(9-7\right)^3\right]\right\}:15\)
\(=107-\left\{38+\left[7.3^2-24:6+2^3\right]\right\}:15\)
\(=107-\left\{38+\left[7.3^2-4+2^3\right]\right\}:15\)
\(=107-\left\{38+\left[63-4+2^3\right]\right\}:15\)
\(=107-\left\{38+\left[59+2^3\right]\right\}:15\)
\(=107-\left\{38+67\right\}:15\)
\(=107-105:15\)
\(=107-7\)
\(=100\)
107 – {38 + [7.32 – 24 : 6+(9 – 7)3]}:15
= 107 - {38+ [7.32 - 24 : 6 + 23 ]} : 15
= 107 - {38 + [ 7.9 - 24 : 6 + 8]} :15
= 107 - {38+[ 63 - 4 + 8]} : 15
= 107 - {38 + 67} : 15
= 107 - 105 : 15
= 107 - 7
= 100
17) 10 – [(82 – 48).5 + (23.10 + 8)] : 28 - 70
= 10 - [(64 - 48).5 + (8.10 +8)] : 28 - 70
= 10 - [16.5 + 88] : 28 - 70
= 10 - [80 + 88] : 28 - 70
= 10 - 168 : 28 - 70
= 10 - 6 - 1
= 3
nếu sai câu nào mong bạn thông cảm ^^
10 - [ ( 82 - 48 ) x 5 + ( 23 x 10 + 8 ) ] : 28
= 10 - [ ( 64 - 48 ) x 5 + ( 8 x 10 + 8 ) ] :28
=10 - [ 16 x 5 + 88 ] :28
=10 - 168 : 28
=10 - 6 = 4
Ý kiến của mình ạ <333
= 10 - [( 64 - 48 ) . 5 + ( 8 . 10 + 8 ) ] : 28
= 10 - [16 . 5 + ( 80 + 8 ) ] : 28
= 10 - [80 + 88] :28
= 10 - 168 : 28
= 10 - 6
= 4
\(a)\)\(47-\left[\left(45.2^4-5^2.12\right)\div14\right]\)
\(=\)\(47-\left[\left(45.16-25.12\right)\div14\right]\)
\(=\)\(47-\left[\left(720-300\right)\div14\right]\)
\(=\)\(47-\left[420\div14\right]\)
\(=\)\(47-30\)
\(=\)\(17\)
\(b)\)\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]\div28\)
\(=\)\(10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]\div28\)
\(=\)\(10-\left[16.5+\left(80+8\right)\right]\div28\)
\(=\)\(10-\left[16.5+88\right]\div28\)
\(=\)\(10-\left[80+88\right]\div28\)
\(=\)\(10-168\div28\)
\(=\)\(10-6\)
\(=\)\(4\)
c) \(2345-1000:\left[19-2\left(21-18\right)^2\right]\)
= \(2345-1000:\left[19-2.3^2\right]\)
= \(2345-1000:\left[19-2.9\right]\)
= \(2345-1000:\left[19-18\right]\)
= \(2345-1000:1\)
= \(1345\)
\(=10-\left[\left(91-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[43.5+88\right]:28\)
\(=10-\left[215+88\right]:28\)
\(=10-303:28\)
\(=10-10,821\)
\(=0,179\)
Ko chắc
\(a.\left(5+2\right).x=36-1\)
\(7.x=35\)
\(x=5\)
\(b.\left(5+1\right).x=75+3\)
\(6.x=78\)
\(x=13\)
\(c.\left(6+1\right).x=5^2+3\)
\(7.x=25+3\)
\(7.x=28\)
\(x=4\)
\(d.\left(7-1\right).x=5^2+3.4-1\)
\(6.x=25+12-1\)
\(6.x=36\)
\(x=6\)
\(a)47-\left[\left(45.2^4-5^2.12\right):14\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]\)
\(=47-30\)
\(=17\)
\(b)50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right)\right]:2+34\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]\)
\(=50-40\)
\(=10\)
\(c)10^2-\left[60:\left(5^6:5^4-3,5\right)\right]\)
\(=10^2-\left[60:\left(5^2-3,5\right)\right]\)
\(=10^2-\left[60:\left(25-3,5\right)\right]\)
\(=10^2-\left[60:21,5\right]\)
\(=100-\dfrac{120}{43}\)
\(=\dfrac{4180}{43}\)
\(d)50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left[10:2+3\right]\)
\(=50-5+3\)
\(=50-8\)
\(=42\)
\(e)10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
\(f)8697-\left[3^7:3^5+2.\left(13-3\right)\right]\)
\(=8697-\left[3^2+2.\left(13-3\right)\right]\)
\(=8697-\left[9+2.10\right]\)
\(=8697-9+20\)
\(=8697-29\)
\(=8668\)
\(g)2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-10^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
\(h)695-\left[200+\left(11-1\right)^2\right]\)
\(=695-\left[200+10^2\right]\)
\(=695-200+100\)
\(=695-300\)
\(=395\)
\(i)129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\left[29-25\right]\)
\(=129-5.4\)
\(=129-20\)
\(=109\)
\(10-\left[\left(8^2-48\right)\cdot5+\left(23\cdot10+8\right):28\right]\)
\(=10-\left[\left(64-48\right)\cdot5+\left(230+8\right):28\right]\)
\(=10-\left(16\cdot5+238:28\right)\)
\(=10-\left(80+\dfrac{17}{2}\right)\)
\(=10-80-\dfrac{17}{2}\)
\(=-17-\dfrac{17}{2}\)
\(=-17-8,5\)
\(=-25,5\)