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4/4/9=2/3:[0,1.x]
0,1.x=2/3:4/4/9 [ chuyen ve]
0,1.x=3/20
x=3/20:0,1
x=3/2
a. \(0,1\left(2\right)=0+\frac{12-1}{90}=\frac{11}{90};0,1\left(3\right)=0+\frac{13-1}{90}=\frac{12}{90}=\frac{2}{15}\)
=> 0,1(2)+0,1(3)=11/90 + 2/15 = 11/90 + 12/90 = 23/90
b. \(0,7\left(3\right)=0+\frac{73-7}{90}=\frac{66}{90}=\frac{11}{15};0,3\left(7\right)=0+\frac{37-3}{90}=\frac{34}{90}=\frac{17}{45}\)
=> 0,7(3)+0,3(7)=11/15 + 17/45 = 33/45 + 17/45 = 50/45 = 10/9
a)\(0,1\left(2\right)+0,1\left(3\right)\)
=\(0,1+0,0\left(2\right)+0,1+0,0\left(3\right)\)
=\(0,2+0,0\left(1\right).2+0,0\left(1\right).3\)
=\(0,2+0,0\left(1\right).5\)
=\(0,2+\frac{1}{90}.5\)
=\(\frac{3,6}{18}+\frac{1}{18}\)
=\(\frac{4,6}{18}\)
3./2:x/ .2 = 20
3./2:x/ = 20:2 = 10
/2:x/ = \(\frac{10}{3}\)
\(\Leftrightarrow\orbr{\begin{cases}2:x=\frac{10}{3}\\2:x=\frac{-10}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{5}\\x=\frac{-3}{5}\end{cases}}\)
Vậy....................................................
\(\frac{\left(0,6\right)^5.\left(0,3\right)^3}{\left(0,2\right)^6.\left(0,3\right)^7}\)
\(=\frac{\left(\frac{6}{10}\right)^5.\left(\frac{3}{10}\right)^3}{\left(\frac{2}{10}\right)^6.\left(\frac{3}{10}\right)^7}\)
\(=\frac{6^5.3^3.\frac{1}{10^8}}{2^6.3^7.\frac{1}{10^{13}}}\)
\(=\frac{2^5.3^5.3^3}{2^6.3^7.\frac{1}{10^5}}\)
\(=\frac{10^5.3}{2}\)
\(=150000\)
0,275-0,3+3/11+3/12-0,625+0,5-5/11-5/12
=11/14-3/10+3/11+3/12-5/8+1/2-5/11-5/12
=(11/14+1/2)-3/10-5/8+(3/11+3/12)+(-5/11-5/12)
=9/7-37/40+[3(1/11+1/12)]+[5(-1/11-1/12)]
=1/280+3+5
=1/280+8
=2441/280
=
\(M=0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}-0,625+0,5-\dfrac{5}{11}-\dfrac{5}{12}\)
\(M=\left(0,375-0,625\right)+\left(0,5-0,3\right)+\left(\dfrac{3}{11}-\dfrac{5}{11}\right)+\left(\dfrac{3}{12}-\dfrac{5}{12}\right)\)
\(M=-0,25+0,2-\dfrac{2}{11}-\dfrac{1}{6}\)
\(M=-\dfrac{263}{660}\)
`(0,3)^{3}.70^{3}`
`=(0,3.70)^{3}`
\(=\left(\dfrac{3}{10}.70\right)^3\\ =\left(3.7\right)^3=21^3=9261\)
\(\left(0,3\right)^3\times70^3\\ =\left(0,3\times70\right)^3\\ =21^3\)