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\(A=\frac{4\cdot0,125\cdot20,2\cdot800\cdot0,25}{1,01\cdot75+0,26\cdot101-1,01}\)
\(=\frac{4\cdot0,25\cdot0,125\cdot800\cdot20,2}{1,01\cdot75+0,26\cdot100\cdot1,01-1,01}\)
\(=\frac{1\cdot100\cdot20,2}{1,01\cdot\left(75+26-1\right)}\)
\(=\frac{100\cdot20,2}{100\cdot1,01}\)
= 20
\(B=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{80}{56}-\frac{15}{12}:\frac{7}{8}\right)\)
\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{10}{7}-\frac{5}{4}\cdot\frac{8}{7}\right)\)
\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{10}{7}-\frac{10}{7}\right)\)
\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot0\)
= 0
(3/10+4/5x1/2):1/8/9-1/1/3
=(3/10+4/10):17/9-4/3
=7/10:17/9-4/3
=63/170-4/3
=-491/510
a) 1,5 x 3 + ( 4,5 - 1,5 x 3 )
= 1,5.3 + ( 4,5 - 4,5)
= 1,5.3 + 0
= 4,5
b) \(\frac{15}{17}\).\(\frac{4}{33}\)+\(\frac{15}{17}\).\(\frac{29}{33}\)
\(=\)\(\frac{15}{17}\)\(\left(\frac{4}{33}+\frac{29}{33}\right)\)
=\(=\frac{15}{17}\)\(.1\)
\(=\frac{15}{17}\)
a) 1,5 x 3 + (4,5 - 1,5 x3)
=4,5 + 0
4,5
b) 15/17 x 4/33 + 15/17 x 29/33
= 15/17 x ( 4/33 + 29/33)
= 15/17 x 33/33
=15/17 x 1
= 1517
c, Lấy 1 trừ cho cả 2 vế
1-2000/2001 = 1/2001
1-2001/2002 = 1/2002
=> 1/2001 > 1/2002
\(a)\frac{41,5\times7,2\times48}{07,2}=1992\)
\(b)47,5\times8\times47,5\times4-95\)
\(=72200-95=72105\)
\(c)\frac{158\times81}{4,5\times2\times18}=\frac{79\times18}{18}=79\)