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de thui
nhung bây giờ mk bận
nên ko giải hộ bn được
chúc bn hoc tốt!
hihi
a) 2x . 7 = 224
2x . 7 = 234256
2x =234256:7
2x =đề sai
b) ( 3x + 5 )2 = 289
( 3x + 5 )2 = 172
=>3x + 5=17
3x=17-5
3x=12
x=12:3
x=4
d) 32x +1 .11 = 2673
32x +1 .11 = 19034163
32x +1 =19034163:11
32x +1 =đề sai
a, 3x+3x*34 = 738
<=> 3x(1+34) =738
<=> 3x *82 = 738
<=> 3x =9 =32
<=> x=2
câu b,c tương tự
a) ( 3x + 5)2 = 289
289 : ( 3x + 5)2 = ( 3x + 5)2
Đổi: 289 = 172
\(\Rightarrow\)3x + 5 = 17
3 . x = 17 - 5
3 . x = 12
x = 12 : 3
x = 4.
b) ( 2x + 1)3 = 1252
( 2x + 1)3 = 125 . 125
( 2x + 1)3 = 15625
Đổi: 15625 = 253
\(\Rightarrow\)2x + 1 = 25
2 . x = 25 - 1
2 . x = 24
x = 24 : 2
x = 12.
c) ( 7x - 11 )3 = 25 . 52 + 200
( 7x - 11 )3 = 2248
Đổi: 1000 = 103
\(\Rightarrow\)7x - 11 = 10
7 . x = 10 + 11
7 . x = 21
x = 21 : 7
x = 3
d) ( 2x - 2 )2 = 643
( 2x - 2 )2 = 262144
Đổi: 262144 = 5122
\(\Rightarrow\) 2x - 2 = 512
2 . x = 512 + 2
2 . x = 514
x = 514 : 2
x = 257
K cho nha , ghi hoài mỏi tay quá!
Cấm Coppy dưới mọi hình thức! Trừ người này : phan thi phuong
a) \(\left(x-1\right)^3=125\)
\(\Leftrightarrow\left(x-1\right)^3=5^3\)
\(\Leftrightarrow x-1=5\)
\(\Leftrightarrow x=5+1\)
\(\Leftrightarrow x=6\)
Vậy \(x=6\)
b) \(2^{x+2}-2^x=96\)
\(\Leftrightarrow\left(2^2-1\right)\cdot2^x=96\)
\(\Leftrightarrow\left(4-1\right)\cdot2^x=96\)
\(\Leftrightarrow3\cdot2^x=96\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
c) \(\left(2x+1\right)^3=343\)
\(\Leftrightarrow\left(2x+1\right)^3=7^3\)
\(\Leftrightarrow2x+1=7\)
\(\Leftrightarrow2x=7-1\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
Vậy \(x=3\)
d) \(720:\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=2^3\cdot5\left(đk:x\ne23\right)\)
\(\Leftrightarrow720:\left(41-2x+5\right)=8\cdot5\)
\(\Leftrightarrow720:\left(46-2x\right)=40\)
\(\Leftrightarrow\dfrac{720}{46-2x}=40\)
\(\Leftrightarrow\dfrac{720}{2\left(23-x\right)}=40\)
\(\Leftrightarrow\dfrac{360}{23-x}=40\)
\(\Leftrightarrow360=40\left(23-x\right)\)
\(\Leftrightarrow9=23-x\)
\(\Leftrightarrow x=23-9\)
\(\Leftrightarrow x=14\left(đk:x\ne23\right)\)
\(\Leftrightarrow x=14\)
Vậy \(x=14\)
e) \(2^x\cdot7=224\)
\(\Leftrightarrow7\cdot2^x=224\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
f) \(\left(3x+5\right)^2=289\)
\(\Leftrightarrow3x+5=\pm17\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+5=17\\3x+5=-17\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{22}{3}\end{matrix}\right.\)
Vậy \(x_1=-\dfrac{22}{3};x_2=4\)
a)\(\left(x-1\right)^3=125\Leftrightarrow\left(x-1\right)^3=5^3\Leftrightarrow x-1=5\Leftrightarrow x=6\)b)\(2^{x+2}-2^x=96\Leftrightarrow2^x.2^2-2^x=96\Leftrightarrow2^x\left(2^2-1\right)=96\Leftrightarrow2^x.3=96\Leftrightarrow2^x=32\Leftrightarrow x=5\)c)\(\left(2x-1\right)^3=343\Leftrightarrow\left(2x-1\right)^3=7^3\Leftrightarrow2x-1=7\Rightarrow2x=8\Rightarrow x=4\)d)\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\Leftrightarrow\left[41-\left(2x-5\right)\right]=720:40=18\)
\(\Leftrightarrow41-2x+5=18\Leftrightarrow36-2x=18\Leftrightarrow2x=18\Leftrightarrow x=9\)
e)\(2^x.7=224\Leftrightarrow2^x=224:7=32\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)
f) \(\left(3x+5\right)^2=289\Leftrightarrow\left(3x+5\right)=17^2\Leftrightarrow3x+5=17\Leftrightarrow3x=12\Leftrightarrow x=4\)
( 3x + 5 ) 2 = 289
( 3x + 5 ) 2 = 172
3x+5=17
3x=17-5
3x=12
x=12:3
x=4