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32.47+47.68- 100 . 17
= (32.47+47.68) - 100 . 17
= 47 (32 + 68) - 100.17
= 47.100 - 100.17
= 100.(47-17)
= 100. 30
= 3000
32.47+47.68- 100 . 17
= 47. ( 32+68 ) - 100.17
=47.100 - 100.17
=100.( 47-17 )
=100.30
=3000
\(a,S_3=-2-2-...-2\)
Tổng có \(\left[\left(2003-1\right):2+1\right]:2=501\left(số.hạng\right)\)
\(\Rightarrow S_3=501\cdot\left(-2\right)=-1002\)
\(b,S_4=\left(-1001+1001\right)+\left(-1000+1000\right)+...+\left(-1+1\right)+1002\\ S_4=1002\)
a: \(S_3=1+\left(-3\right)+5+\left(-7\right)+...+2001+\left(-2003\right)\)
=(-2)+(-2)+...+(-2)
=-2004
\(\left(9^{98}\cdot80+9^{98}\right):9^{100}\)
\(=\frac{9^{98}\cdot80+9^{98}}{9^{100}}\)
\(=\frac{9^{98}\cdot\left(80+1\right)}{9^{100}}\)
\(=\frac{9^{98}\cdot81}{100}\)
\(=\frac{9^{98}\cdot9^2}{9^{100}}\)
\(=\frac{9^{100}}{9^{100}}=1\)
100:{250:[450-(500-\(2^2\).25)]}
=100:{250:[450-(500-4.25)]}
=100:{250:[450-(500-100)]}
=100:{250:[450-400]}
=100:{250:50}
=100:50
=2
100:(250:[450-(500-4.25)]
=100:(250:(450-(500-100)]
=100:(250:(450-400)]
=100:(250:50)
=100:5
=20
45 x 74 + 45 x 26 - 120
= 45 x (74 + 26) - 120
= 45 x 100 - 120
= 4500 - 120
= 4380
abcabc : 1001 + abc
= abc + abc
= 2 x abc
= 2abc
5 x 34 x 20 + 125 x 64 + 25 x 74 x 22
= 5 x 34 x 20 + 25 x 5 x 64 + 25 x 32 x 22
= 5 x 25 x (34 + 32 + 22 + 20 + 64)
= 5 x 25 x 174
= 5 x 24 + 25 x 100
= 2620
\(1001\left(\frac{2}{12012}+\frac{74}{555555}-\frac{2}{13.7.11.5}\right)=\frac{1001.2}{12012}+\frac{1001.74}{555555}-\frac{1001.2}{13.11.7.5}=\frac{1001.2}{12.1001}+\frac{1001.2.37}{1001.37.15}-\frac{1001.2}{1001.5}\)\(=\frac{1}{6}+\frac{2}{15}-\frac{2}{5}=\frac{5}{30}+\frac{4}{30}-\frac{12}{30}=-\frac{3}{30}=-\frac{1}{10}\)
[47.(32+68):100].1001=(47.100:100).1001=47.1001=47047
[ ( 47.32 +47.68) :100] .1001
= [ ( 47 . 32 + 68) :100] .1001
= [ ( 47 . 100 ) : 100 ] . 1001
= [ ( 4700 ) : 100 ] . 1001
= [ 4700 : 100 ] . 1001
= 47 . 1001
= 47047