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\(\dfrac{-3}{8}.16\dfrac{8}{17}-0,375.7\dfrac{9}{17}\)
\(=\dfrac{3}{8}.\dfrac{-280}{17}-\dfrac{3}{8}.\dfrac{128}{17}\)
\(=\dfrac{3}{8}.\left(\dfrac{-280}{17}-\dfrac{128}{17}\right)\)
\(=\dfrac{3}{8}.-24\)
\(=-9\)
a) =-2,5+ -5,9+2/5
= (-2/5+2/5)+-5/9
= 0+-5/9
=-5/9
b) 17/13 - 4/13 + 11
= 1+11
= 12
c) 3/5 x (18/17+9/17 - 10/17)
= 3/5 x 1
= 3,5
\(\frac{32}{17}:\frac{9}{2}+\frac{35}{17}:\frac{9}{3}+\frac{35}{17}:\frac{9}{4}\)
\(=\frac{32}{17}:\left(\frac{9}{2}+\frac{9}{3}+\frac{9}{4}\right)\)
\(=\frac{32}{17}:\frac{39}{4}\)
\(=\frac{128}{663}\)
\(a,18.17-3.6.7\)
\(=18.17-18.7\)
\(=18.\left(17-7\right)\)
\(=18.10\)
\(=180\)
\(b,54-6.\left(17+9\right)\)
\(=54-6.17+6.9\)
\(=54-102+54\)
\(=\left(54+54\right)-102\)
\(=108-102\)
\(=6\)
\(c,33.\left(17-5\right)-17.\left(33-5\right)\)
\(=33.17-33.5-17.33-17.5\)
\(=\left(33.17-17.33\right)-\left[5\left(33-17\right)\right]\)
\(=0-5.16\)
\(=-80\)
a)=18.17-18.7
=18.(17-7)=18.10=180
b)=54-(6.17+6.9)=54-102-54=(54-54)-102=0-102=-102
c)=(33.17-33.5)-(17.33-17.5)=33.17-33.5-17.33+17.5=(33.17-17.33)-5.(33-17)=0-80=-80
\(\dfrac{-3}{8}\cdot16\cdot\dfrac{8}{17}-0,375\cdot7\cdot\dfrac{9}{17}\)
\(=-\dfrac{3}{8}\cdot\dfrac{128}{17}-\dfrac{3}{8}\cdot\dfrac{63}{17}\)
\(=-\dfrac{3}{8}\left(\dfrac{128}{17}+\dfrac{63}{17}\right)=-\dfrac{3}{8}\cdot\dfrac{191}{17}=\dfrac{-573}{136}\)
- \(\dfrac{3}{8}\).16.\(\dfrac{8}{17}\) - 0,375.7\(\dfrac{9}{17}\)
Đề như này phải không em?