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\(a.35\cdot9-35\cdot7\\ =35\cdot\left(9-7\right)\\ =35\cdot2=70\\ b.536\cdot8-536\cdot6\\ =536\cdot\left(8-6\right)\\ =536\cdot2=........\)
a) \(35\times9-35\times7=35\times\left(9-7\right)=35\times2=70\)
b) \(536\times8-536\times6=536\times\left(8-6\right)=536\times2=1072\)
=1/(1x3)x1/(2x4)x...x1/(9x11)
=1/(1x3x2x4x...x9x11)
=1/(1x2x3x3x4x4x5x5x...x9x10x11)
a)136-x=400/8+7
136-x=50+7
136-x=57
x=136-57
x=79
b)x+x+x+15=21
3x=21-15
3x=6
x=6/3
x=2
c)35+x+27=80
62+x=80
x=80-62
x=18
a)136-x=400:8+7
136-x=57
x=136-57
x=79
b)x+x+x+15=21
x*3+15=21
x*3=21-15
x=6:3
x=2
c)35+x+27=80
35+x=80-27
x=53-35
x=18
2/3 = 2 x 4/ 3 x 4 =8/12
8/14 = 8 : 2/ 14 : 2 =4/7
5/9 = 5 x3/ 9 x 3 =15/37
35/ 40 = 35 : 5/ 40 : 5=7/8
1/3x1/8x...x1/99
=1/(1x3)x1/(2x4)x...x1/(9x11)
=1/(1x3x2x4x...x9x11)
=1/(1x2x3x3x4x4x5x5x...x9x9x10x11)
\(\dfrac{x}{5}\) = \(\dfrac{48}{60}\)
\(x\) = \(\dfrac{48}{60}\) \(\times\) 5
\(x\) = 4
\(\dfrac{x}{7}\) = \(\dfrac{16}{56}\)
\(x\) = \(\dfrac{16}{56}\) \(\times\) 7
\(x\) = 2
\(\dfrac{8}{x}\) = \(\dfrac{72}{108}\)
\(x\) = 8 : \(\dfrac{72}{108}\)
\(x\) = 12
\(x\) - \(\dfrac{3}{12}\) = \(\dfrac{35}{84}\)
\(x\) = \(\dfrac{35}{84}\) + \(\dfrac{3}{12}\)
\(x\) = \(\dfrac{2}{3}\)
\(\frac{6-2}{5}+\frac{3}{5.3}\)
\(=\frac{4}{5}+\frac{1}{5.1}\)
\(=\frac{4}{5}+\frac{1}{5}\)
\(=\frac{5}{5}=1\)
a. 6 x 3 - ( \(\frac{2}{5}+\frac{3}{5}\)) = 6 x 3 - \(\frac{5}{5}\)= 6 x 3 - 1 = 18 - 1 = 17
b.( \(\frac{31}{35}-\frac{4}{7}\)) x \(\frac{8}{7}\): 2 =\(\frac{11}{35}\)x \(\frac{8}{7}\): 2 =\(\frac{88}{245}\): 2 = \(\frac{88}{490}\)= \(\frac{44}{245}\)= ...........rút gọn đến khi hết