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Ta có a - b = 4
suy ra a > b
ta có các cặp ab: 40; 51;62;73;84;95
sau đó b lần lượt thay số thì sẽ ra kết quả là a=8 ; b=4 nhé
#chanh
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1=3/3=4/4=5/5=...
=> 1+1/1*3=3/1*3=1/1
=> 1+1/2*4=4/2*4=1/2
=>...
Bieu thuc se con lai la 1*1/2*1/3*1/4*1/5
Vay A=1/120
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\(\frac{6}{5}\)x 5 - \(\frac{17}{5}\)= \(\frac{30}{5}\)- \(\frac{17}{5}\)=\(\frac{13}{5}\)
ta có:4/5*5+4\10*5)-17/5
=20/5+20/10)-17/5
=50/10-17/5
=10/1+(-17)/5
=-33/5
mk nghĩ là vậy !nếu mk làm sai thìcho mk xin lỗi ! đúng thì tích cho mk!nếu k hiểu hỏi lại nha
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a) \(\frac{2\cdot3\cdot5}{70}=\frac{30}{70}=\frac{3}{7}\)
b) \(\frac{2\cdot6\cdot11}{33\cdot24}=\frac{2\cdot6\cdot11}{3\cdot11\cdot2\cdot2\cdot6}=\frac{1}{6}\)
c) \(\frac{21\cdot45}{9\cdot7\cdot5\cdot3}=\frac{3\cdot7\cdot5\cdot9}{9\cdot7\cdot5\cdot3}=1\)
Chúc bạn học tốt.
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\(x-67421=5678\)
\(x=5678+67421\)
\(x=73099\)
\(x-\left(562+236\right)x5=569\)
\(x-798=569:5\)
\(x-798=113,8\)
\(x=113,8+798\)
\(x=911,8\)
\(x-231x3=263\)
\(x-693=263\)
\(x=263+693\)
\(x=956\)
\(x-560:4=426x9\)
\(x-140=3834\)
\(x=3834+140\)
\(x=3974\)
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(a+b) x 2=88 => a+b=44
(b+c) x 2= 148 => b+c=74
(a+c) x 2=108 => a+c=54
(c+d) x 2=208 => c+d=104
(b+d) x 2=188 => b+d=94
(a+d) x 2=148 => a+d= 74
=> a+b+b+c+a+c+c+d+b+d+a+d = 44+74+54+104+94+74
=> 3 x a + 3 x b + 3 x c + 3 x d = 444
3 x (a+b+c+d) = 444
a+b+c+d = 444 : 3
a+b+c+d = 148
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dau . la dau x
a/ 1.3.2.4.3.5.4.6.5.7/2.2.3.3.4.4.5.5.6.6=1.7/2.6=7/12
b/ ab.aba=abab
aba=abab:ab
aba=101
=>a=1 b=0
aabb : ab = 99 hay ab x 99 = aabb hay ab x100 – ab = aabb
Ta có phép tính
__ ab00
___ab___
aabb
b=0 hoặc b=5
Nếu b=0 thì a000 – a0 = aa00 (sai)
Nếu b=5 thì
__ a500
__a5___
aa55
a=4
c) thay a=7/6 b=6/5 thi 3 x a + 4 : b - 5/12=3.7/6+4.6/5-5/12=7/2+24/5-5/12=210/60+288/60-25/60=473/60
**** nha
\(\frac{1.3.2.4.3.5.4.6.5.7}{2.2.3.3.4.4.5.5.6.6}=\frac{\left(2.3.4.5.6\right).\left(3.4.5.7\right)}{\left(2.3.4.5.6\right).\left(2.3.4.5.6\right)}=\frac{7}{12}\)
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1 \(A=\left(1+\frac{1}{2}\right)\times\left(1+\frac{1}{3}\right)\times\left(1+\frac{1}{4}\right)\times.........\times\left(1+\frac{1}{2016}\right)\times\left(1+\frac{1}{2017}\right)\)
\(A=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times......\times\frac{2016}{2017}\times\frac{2018}{2017}\)
\(A=\frac{2018}{2}=1009\)
\(B=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+.......+\frac{2}{43.45}\)
\(B=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-......+\frac{1}{43}-\frac{1}{45}\)
\(B=\frac{1}{3}-\frac{1}{45}\)
\(B=\frac{14}{45}\)
2 \(\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{2018}\times\frac{2017}{47}\)
\(=\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{47}\times\frac{2017}{2018}\)
\(=\frac{2017}{2018}\times\left(\frac{23}{47}+\frac{24}{47}\right)\)
\(=\frac{2017}{2018}\times1\)
=\(\frac{2017}{2018}\)
bạn nào xem giải thế có đúng ko
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ab . 9 = a0b
( 10a + b ) x 9 = 100a + b
90a + 9b = 100a + b
8b = 10a
=> a/b = 4/5 = 8/10
=> \(\orbr{\begin{cases}a=4;b=5\\a=8;b=10\end{cases}}\)
Ta có:\(\overline{ab}\cdot9=\overline{a0b}\)
\(\left(10a+b\right)\cdot9=100a+b\)
\(90a+9b=100a+b\)
\(8b=10a\)(giảm mỗi bên 90a+b)
\(4b=5a\)
Mà chỉ có a=4;b=5 là thỏa mãn
Vậy a=4;b=5
$\overline{ab}$ $= ( a+ b ) \times 5$
$ 10 \times a + b = a \times 5 + b \times 5`
$ 5 \times a = b \times 4`
Do `a;b` là các số tự nhiên nên `a=4;b=5`
\(\Rightarrow\) $\overline{ab}$ $=45$
Vậy ....