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28 tháng 10 2020

\(\frac{5}{17}-\frac{11}{13}+\frac{12}{17}+\frac{27}{13}+\left(-2020\right)^2\)

\(=\left(\frac{5}{17}+\frac{12}{17}\right)+\left(\frac{-11}{13}+\frac{27}{13}\right)+\left(-2020\right)^2\)

\(=1+\frac{16}{13}+\left(-2020\right)^2\)\(=1+\frac{16}{13}+4080400\)

\(=4080402\frac{3}{13}\)

11 tháng 8 2017

a) \(\frac{-77}{143}+\frac{65}{143}-\frac{66}{143}+\frac{7}{22}\)

\(\frac{-78}{143}+\frac{7}{22}\)\(\frac{-6}{11}+\frac{7}{22}\)\(\frac{-12}{22}+\frac{7}{22}\)

\(\frac{-5}{22}\)

b) \(\frac{-4}{5}-\frac{20}{170}+\frac{51}{170}+\frac{150}{170}\)\(\frac{-4}{5}-\frac{221}{170}\)

\(\frac{-4}{5}-\frac{13}{10}\)\(\frac{-8}{10}-\frac{13}{10}\)=\(\frac{-21}{10}\)

25 tháng 12 2015

\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}+\frac{x+2}{13^{13}}\)

=> \(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}-\frac{x+2}{12^{12}}-\frac{x+2}{13^{13}}=0\)

=> \(\left(x+2\right)\left(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\right)=0\)

Vì \(\frac{1}{10^{10}}+\frac{1}{11^{11}}\ne\frac{1}{12^{12}}+\frac{1}{13^{13}}\Rightarrow\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\ne0\)

=> \(x+2=0\Rightarrow x=-2\)

4 tháng 10 2021

yutyugubhujyikiu

15 tháng 5 2017

a) Thiếu đề (hoặc sai)

b) x đâu?

c)\(3x-1=x+2\)

\(\Rightarrow3x-x=2+1\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\frac{3}{2}\)

c) \(\frac{x+2}{5}=\frac{2-3x}{3}\)

\(\Rightarrow3.\left(x+2\right)=5.\left(2-3x\right)\)

\(\Rightarrow3x+6=10-15x\)

\(\Rightarrow3x+15x=10-6\)

\(\Rightarrow18x=4\)

\(\Rightarrow x=\frac{4}{18}=\frac{2}{9}\)

15 tháng 5 2017

câu 1 là \(x\times\left(4.6+\frac{3}{5}\right)=7.2-8.15\)

câu 2 là \(42+\frac{3}{7}.\left[3\times x-1=12\right]\)

26 tháng 6 2017

câu 1=0

câu 2=3.

5 tháng 9 2019

A = 5/7.(1+9/13) − 5/7.9/13

A= 5/7.(1+9/13 - 9/13)

A = 5/7.1

A = 5/7

B = 11/24 − 5/41 + 13/24 + 0.5 − 36/41

B = (11/24 + 13/24) - (5/41 + 36/41) + 0.5

B = 1 - 1 + 0.5

B = 0.5

C = −4/13.5/17 + (−12/13).4/17 + 4/13

C = 4/13.(-5/17) + (−12/13).4/17 + 4/13

C = 4/13.(-5/17 + 1) + (−12/13).4/17

C = 4/13.(−12/17) + (−12/13).4/17

C = (4.-12)/(13.17) + (−12/13).4/17

C = 4/17.(−12/13) + (−12/13).4/17

C = 4/17.(−12/13).2

C = 96/221

D = (4/3 − 3/2)2 − 2.∣−1/9∣ + (−5/18)

D = (4/3 − 3/2)2 − 2.1/9+ (−5/18)

D = -1/62 - 2/9+ (−5/18)

D = -1/12 - ( 2/9+ (−5/18) )

D = -1/12 - ( 4/18+ (−5/18) )

D = -1/12 - (-1/18)

D = -1/12 + 1/18

D = -3/36 + 2/36

D = -1/36

E = (−3/4 + 2/3):5/11 + (−1/4 + 1/3):5/11

E = (−3/4 + 2/3 + (−1/4) + 1/3):5/11

E = ((−3/4 + (−1/4)) + (2/3 + + 1/3)):5/11

E = ( - 1 + 1):5/11

E = 0:5/11

E = 0

\(\text{1. Ta có hai trường hợp :}\)

\(\text{ TH1 : 3x = 0}=>x=0.\)

\(\text{ TH2 : x -}\frac{1}{2}=2=>x=\frac{5}{2}.\)

\(\text{Vậy x = 0 , x = }\frac{5}{2}.\)

26 tháng 6 2019

\(1,\)\(3x\left(x-\frac{1}{2}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-\frac{1}{2}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{2}\end{cases}}}\)

\(2,\)\(\left(\frac{4}{3}+\frac{2}{5}\right)-x=\frac{1}{2}+\frac{1}{3}\)

\(\Rightarrow x=\frac{4}{3}+\frac{2}{5}-\frac{1}{2}-\frac{1}{3}\)

\(\Rightarrow x=1+\frac{4}{10}-\frac{5}{10}=1-\frac{1}{10}=\frac{9}{10}\)