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Ta có: Trong các đơn vị đo thể tích đơn vị bé = 1/1000 đơn vị lớn
Mà ở đây ta có E = 1cm3 = 1/1000dm3
=> Đáp án đúng là E
Mình không nghĩ ra nên bạn tham khảo nhé :
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Theo bài ra \(\frac{2}{5}\)số gà ít hơn \(\frac{2}{3}\)số vịt là 200 con
Vậy, \(\frac{6}{5}\)số gà ít hơn 2 lần số vịt là:
200 x 3 = 600 (con)
Hay \(\frac{3}{5}\)số gà ít hơn vịt là
600 : 2 = 300 con (1)
Mặt khác, \(\frac{3}{4}\)số gà nhiều hơn \(\frac{5}{12}\)số vịt là 125 con
Nên 9 lần số gà nhiều hơn 5 lần số vịt là:
125 x 12 = 1500 (con)
Hay \(\frac{9}{5}\)số gà nhiều hơn số vịt là:
1500 : 5 = 300 con (2)
Từ (1) và (2) ta có:
\(\frac{9}{5}\)số gà nhiều hơn \(\frac{3}{5}\)số gà số con là
300 + 300 = 600 (con)
Phân số chỉ số phần của 600 con gà là:
\(\frac{9}{5}-\frac{3}{5}=\frac{6}{5}\)
Số gà là:
600 x 5 : 6 = 500 (con)
Số vịt là:
3 x 500:5 + 300 = 600 (con)
Đáp số: 500 con gà
600 con vịt
500 con gà
600con vịt
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800 + ab = 17 x ab
800 = 17 x ab - ab
800 = 16 x ab
ab = 800:16
ab = 50
Vậy: 850 : 50 = 17
Có số cái bắt tay là :
100x99:2=4950(cái)
Đáp số : 4950 cái
Ta có: Số nhỏ nhất chia hết cho 3 trong khoảng từ 1000 đến 9999 là 1002
Số lớn nhất chia hết cho 3 trong khoảng từ 1000 đến 9999 là 9999
Số các số tự nhiên từ 1000 đến 9999 là: 9999 - 1000 + 1 = 9000
Số các số chia hết cho 3 trong khoảng từ 1000 đến 9999 là: \(\frac{9999-1002}{3}\)+ 1 = 3000
Số các số không chia hết cho 3 là: 9000 - 3000 = 6000
Chúc bạn học tốt!~
Ta có: Từ 1000 đến 9999 có tất cả \(\left(9999-1000\right)\div1+1=9000\)(số )
Từ 1000 đến 9999 có tát cả các số chia hết cho 3 là: \(\left(9999-1002\right)\div3+1=3000\)(số)
Vậy có tất cả \(9000-3000=6000\)(số) không chia hết cho 3
Học tốt
n = 6
KB mk và k đúng cho mk nha mọi ng
#_TL :
( n -1)3 = 125
( n -1 )3 = 53
=> n - 1 = 5
=> n= 6
Hok tốt ạ :33