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=(-1/2) : (-2/3) :( -3/4) :...: (-49/50)
= -1/2 . (-3/2) . (-4/3) . ... . (-50/49)
= -1/2.(-1/2) . (-50)
= - 1/100
f(x)=9x3-1/3x+3x2-3x+1/3x2-1/9x3-3x2-9x+27+3x
= 9x3-1/9x3+3x2+1/3x2-3x2-1/3-3x-9x+3x+27
= 80/9x3+1/3x2-28/3x+27
\(\left[\frac{139}{84}-\frac{577}{924}-\frac{98}{205}\right].\frac{2197}{27}\)
\(\left[\frac{34}{33}-\frac{98}{205}\right]\frac{2197}{27}\)
\(\frac{3736}{6765}.\frac{2197}{27}=44,93713285\)
a) \(\frac{45^{10}.5^{20}}{75^{15}}\)
=
\(\frac{\left(5.9\right)^{10}.5^{20}}{\left(5.15\right)^{15}}\)
= \(\frac{5^{10}.9^{10}.5^{20}}{5^{15}.15^{15}}\)
= \(\frac{5^{10}.3^{20}.5^{20}}{5^{15}.15^{15}}\)
= \(\frac{5^{10}.15^{20}}{5^{15}.15^{15}}\)
= \(\frac{15^5}{5^5}\)
= \(\frac{3^5.5^5}{5^5}\)
= \(3^5\)
b) \(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}\)
= \(\frac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}\)
= \(\frac{2^5}{0,4}\)
= \(2^5\) : 0,4
(=) 32 : \(\frac{2}{5}\)
= 90
c) \(\frac{2^{15}.9^4}{6^6.8^3}\)
= \(\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}\)
= \(\frac{2^{15}.3^8}{2^6.3^6.2^9}\)
= \(3^2\)
a) \(\frac{125^5}{5^{15}}=\frac{\left(5^3\right)^5}{5^{15}}=\frac{5^{15}}{5^{15}}=1\)
Mk không rảnh cho lắm !! nên chỉ làm câu a thui mấy câu khác để suy nghĩ đã
T nha
b) \(\left(\frac{2}{3}^{21}\right):\left(\frac{4}{9}^{10}\right)=\left(\frac{2}{3}^{21}\right):\left(\frac{2}{3}^2\right)^{10}=\left(\frac{2}{3}^{21}\right):\left(\frac{2}{3}^{20}\right)=\frac{2}{3}\)
Ta có: \(\left(\frac{3}{5}\right)^n=\left(\frac{9}{25}\right)^5\)
\(\Rightarrow\left(\frac{3}{5}\right)^n=\left(\frac{3}{5}\right)^{2\times5}\)
\(\Rightarrow n=2\times5=10\)
Vậy n = 10.