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a)nZn=m/M=6,5/65=0,1(mol)
PT: Zn + 2HCl -> ZnCl2 + H2
cứ: 1.............2...........1.........1 (mol)
vậy: 0,1----->0,2------->0,1-->0,1(mol)
b) VH2(đkc)=n.22,4=0,1.22,4=2,24(lít)
c) mZnCl2=n.M=0,1.136=13,6(g)
Gọi \(\left\{{}\begin{matrix}n_{Ca}:x\left(mol\right)\\n_{CaCO3}:y\left(mol\right)\end{matrix}\right.\)
\(Ca+2HCl\rightarrow CaCl_2+H_2\)
x_____2x_____x_________x
\(CaCO_3+2HCl\rightarrow CaCl_2+CO_2+H_2O\)
y________2y________y________y_________
\(\Rightarrow\left\{{}\begin{matrix}40x+100y=24\\x+y=\frac{6,72}{22,4}=0,3\left(mol\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,1\left(mol\right)\\y=0,2\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{Ca}=\frac{0,1.40}{24}.100\%=16,67\%\\\%m_{CaCO3}=100\%-16,67\%=83,33\%\end{matrix}\right.\)
\(n_{HCl\left(bđ\right)}=\left(0,1.2+0,2.2\right).110\%=0,66\left(mol\right)\)
\(V_{dd\left(HCl\right)}=\frac{0,66}{2}=0,33\left(l\right)\)
\(\Rightarrow CM_{CaCl2}=\frac{0,1+0,2}{0,33}=0,9M\)
Bài 1. nso2=12.8/64=0.2(mol)
nNaOH=1x0.25=0.25(mol)
t=0.25/0.2=0.05
SO2 + NaOH ---> NaHSO3
mNaHSO3=n x M= 0.2 x 104=20.8(g)
Bướm
a) nH2 = 3,316/22,4= 0,14(mol)
PTHH: Mg + 2 HCl -> MgCl2 + H2
x________2x____________x__x(mol)
Zn+ 2 HCl -> ZnCl2 + H2
y_____2y____y_________y(mol)
=> \(\left\{{}\begin{matrix}24x+65y=5\\x+y=0,14\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,1\\y=0,04\end{matrix}\right.\)
nHCl=2.nH2=0,28(mol)=>mHCl=0,28.36,5=10,22(g)
=>VddHCl=(10,22.100)/20=51,1(g)
b) mddsau=mkl+mddHCl-mH2= 5+51,1-0,14.2=55,82(g)
mMgCl2= 95.0,1=9,5(g)
mZnCl2=136.0,04=5,44(g)
=> \(C\%ddMgCl2=\frac{9,5}{55,82}.100\approx17,019\%\\ C\%ddZnCl2=\frac{5,44}{55,82}.100\approx9,746\%\)
Cu ko pư => mCu = 3.2
=> mAl, Fe = 14.2 - 3.2 = 11
2Al + 6HCl --------> 2AlCl3 + 3H2
Fe + 2HCl ----------> FeCl2 + H2
nH2 = 8.96/22.4 = 0.4
Ta có hpt
27x + 56y = 11
1.5x + y = 0.4
Giải hpt
x = 0.2
y = 0.1
a.
mAl = 27*0.2 = 5.4
%mAl = 5.4*100/14.2 = 38%
%mCu = 3.2*100/14.2 = 22.5%
=> %mFe = 100 - (38 - 22.5) = 39.5%
b.
nHCl = 6x + 2y = 1.4
=> V HCl = 1.4/1.5 = 0.93M
Ý cuối ko hỉu cho b(g) sao tìm a