Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
(m : 1 - m x 1) : (m x 2008 + m + 2008)
= (m - m) : (m x 2008 + m + 2008)
= 0 : (m x 2008 + m + 2008)
= 0
\(H=\left(m:1-mx1\right):\left(mx1991+m+1\right)\)
\(=\left(m-m\right):\left(mx1991+m+1\right)\)
\(=0:\left(mx1991+m+1\right)\)
\(=0\)
H = ( m : 1 - m x 1 ) : ( m x 1991 + m+ 1 )
H = ( m - m ) : ( m x 1991 + m + 1 )
H = 0 : ( m x 1991 + m +1 )
H = 0
870 - x : 11 x 87 = 261
x : 11 x 87 = 870 - 261
x : 11 x 87 = 609
x : 11 = 609 : 87
x : 11 = 7
x = 7 x 11
x = 77
x : 0.25 x 2.3 = 6.9
x : 0.25 = 6.9 : 2.3
x : 0.25 = 3
x = 3 x 0.25
x = 0.75
2 x (y + y) = 8.16
y + y = 8.16 : 2
y x 2 = 4.08
y = 4.08 : 2
y = 2.04
y x 1.5 + y + y x 7.5 = 59.8
y x (1.5 + 1 + 7.5) = 59.8
y x 10 = 59.8
y = 59.8 : 10
y = 5.98
m : 1/6 + m : 0.25 = 152
m : 1/6 + m : 1/4 = 152
m x 6 + m x 4 = 152
m x (6 + 4) = 152
m x 10 = 152
m = 152 : 10
m = 15.2
m : 1/3 + m : 0.25 = 1.4
m : 1/3 + m : 1/4 = 1.4
m x 3 + m x 4 = 1.4
m x (3 + 4) = 1.4
m x 7 = 1.4
m = 1.4 : 7
m = 0.2
`@` `\text {Ans}`
`\downarrow`
`a,`
\(\text{326 x 728 + 327 x 272}\)
`= 326 \times 728 + 326 \times 272 + 272`
`= 326 \times (728 + 272) + 272`
`= 326 \times 1000 + 272`
`= 362000 + 272`
`= 362272`
`b,`
\(\text{2008 x 867 + 2009 x 133}\)
`= 2008 \times 867 + 2008 \times 133 + 133`
`= 2008 \times (867 + 133) + 133`
`= 2008 \times 1000 + 133`
`= 2008000 + 133`
`= 2008133`
`c,`
\(\text{1235 x 6789 x (630 - 315 x 2 )}\)
`= 1235 \times 6789 \times (630 - 630)`
`= 1235 \times 6789 \times 0`
`= 0`
`d,`
\((m \div 1 - m \times 1 ) \div ( m \times 2008 + m + 2008)\)
`= (m - m) \div (m \times 2008 + m + 2008)`
`= 0 \div (m \times 2008 + m + 2008)`
`= 0`
a: =326*728+326*272+272
=326000+272
=326272
c: \(=1235\cdot6789\cdot\left(630-630\right)=0\)
d: \(=\left(m-m\right):\left(20009m+2008\right)=0\)
bài 1"
121/27 x 54/11 < n < 100/21 : 25/126
=> 22 < n < 24
mà n là số tự nhiên
=> n = 23
Bài 2:
(m:1 - m x 1) : ( m x 2005 + m + 1)
= (m-m) : ( m x 2005 + m + 1)
= 0 : (m x 2005 + m + 1) = 0
1.
\(\frac{121}{27}\times\frac{54}{11}< n< \frac{100}{21}:\frac{25}{126}\)
=> \(22< n< 24\)
Mà n là số tự nhiên
=> n = 23
2.
( m : 1 + m x 1 ) : ( m x 2005 + m + 1 )
= ( m - m ) : ( m x 2005 + m + 1 )
= 0 : ( m x 2005 + m + 1 )
= 0
(m : 1 - m x 1) : (m x 2018 + m+2018)
= (m-m) : ( m x 2018 +m +2018)
= 0 :( m x 2018 + m +2018)
=0