Question

[leeily]

\(\left\{\left[\left(\dfrac{1}{25}-0,6\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\left[\left(-\dfrac{1}{3}\right)+\dfrac{1}{2}\right]\)

Giúp mk với 😭

Answer 1

[Phùng Phạm Quỳnh Trang]

mk ko nghi lại đề nx nhé.

= { [ ( -0,56)² : 49/125 ] . 5/6 } - ( 1/6 )

=( 0,8 . 5/6)  - 1/6

=  ( 8/10 . 5/6 ) - 1/6

= ( 4/5 . 5/6 ) - 1/6

= 2/3 - 1/6

= 1/2 

Answer 2

[Phạm Thị Diễm My]

=\(\left\{\left[\left(\dfrac{1}{25}-\dfrac{3}{5}\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\left[\left(\dfrac{-2}{6}\right)+\dfrac{3}{6}\right]\)

\(=\left\{\left[\left(\dfrac{1}{25}-\dfrac{15}{25}\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)

\(=\left\{\left[\left(\dfrac{-14}{25}\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)

\(=\left\{\left[\dfrac{196}{625}.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)

\(=\left\{\dfrac{4}{5}.\dfrac{5}{6}\right\}-\dfrac{1}{6}\)

\(=\dfrac{2}{3}-\dfrac{1}{6}\)

\(=\dfrac{4}{6}-\dfrac{1}{6}\)

\(=\dfrac{3}{6}=\dfrac{1}{2}\)