\(\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\left(\frac{-3}{8}\right)\)

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26 tháng 8 2015

(-2).-38/21.-7/4.-3/8

=19/8

26 tháng 8 2015

bài nãy dễ mà bạn

\(\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\frac{\left(-3\right)}{8}=\frac{-2.\left(-38\right).\left(-7\right).\left(-3\right)}{21.4.8}=\frac{4.19.21}{21.4.8}=\frac{19}{8}\)

23 tháng 9 2016

bai de the ma cung hoi

23 tháng 8 2016

\(\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\frac{-3}{8}\)

\(=\left(-2.\frac{-7}{4}.\frac{-3}{8}\right).\frac{-38}{21}\)

\(=\left(\frac{7}{2}.\frac{-3}{8}\right).\frac{-38}{21}\)

\(=\frac{-21}{16}.\frac{-38}{21}\)

\(=\frac{-38}{-16}=\frac{19}{8}\)

23 tháng 8 2016

\(\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\left(\frac{-3}{8}\right)\)

\(=\left(-2.\frac{-7}{2}.\frac{-3}{8}\right).\frac{-38}{21}\)

\(=\left(7.\frac{-3}{8}\right).\frac{-38}{21}\)

\(=\frac{-21}{8}.\frac{-38}{21}\)

\(=\frac{-38}{-8}=\frac{19}{4}\)

4 tháng 10 2021

yutyugubhujyikiu

...
Đọc tiếp

\(\left(\frac{-5}{12}+\frac{7}{4}-\frac{3}{8}\right)-\left[4\frac{1}{2}-7\frac{1}{3}\right]-\left(\frac{1}{4}-\frac{5}{2}\right)\)

\(\left[2\frac{1}{4}-5\frac{3}{2}\right]-\left(\frac{3}{10}-1\right)-5\frac{1}{2}+\left(\frac{1}{3}-\frac{5}{6}\right)\)

\(\frac{4}{7}-\left(3\frac{2}{5}-1\frac{1}{2}\right)-\frac{5}{21}+\left[3\frac{1}{2}-4\frac{2}{3}\right]\)

\(\frac{1}{8}-1\frac{3}{4}+\left(\frac{7}{8}-3\frac{7}{2}+\frac{3}{4}\right)-\left[\frac{7}{4}-\frac{5}{8}\right]\)

\(\left(\frac{3}{5}-2\frac{1}{10}+\frac{11}{20}\right)-\left[\frac{-3}{4}+1\frac{7}{2}\right]\)

\(\left[-2\frac{1}{5}-2\frac{2}{3}\right]-\left(\frac{1}{15}-5\frac{1}{2}\right)+\left[\frac{-1}{6}+\frac{1}{3}\right]\)

\(1\frac{1}{8}-\left(\frac{1}{15}-\frac{1}{2}+\frac{-1}{6}\right)+\left[\frac{5}{4}+\frac{3}{2}\right]\)

\(\frac{5}{6}-\left(1\frac{1}{3}-1\frac{1}{2}\right)+\left[\frac{5}{12}-\frac{3}{4}-\frac{1}{6}\right]\)

\(1\frac{1}{4}-\left(\frac{7}{12}-\frac{2}{3}-1\frac{3}{8}\right)+\left[\frac{5}{24}-2\frac{1}{2}\right]-\frac{1}{6}-\left[\frac{-3}{4}\right]\)

\(-2\frac{1}{5}+2\frac{3}{10}-\left(\frac{6}{20}-\left[\frac{2}{8}-1\frac{1}{2}\right]\right)+\left[\frac{7}{20}-1\frac{1}{4}\right]\)

\(-\left[1\frac{2}{3}-3\frac{1}{2}+\frac{1}{4}\right]+\left(\frac{2}{6}-\frac{5}{12}\right)-\left(\frac{1}{3}-\left[\frac{1}{4}-\frac{1}{3}\right]\right)\)

\(-\frac{4}{5}-\left(1\frac{1}{10}-\frac{7}{10}\right)+\left[\frac{3}{4}-1\frac{1}{5}\right]+1\frac{1}{2}\)

\(\frac{3}{21}-\frac{5}{14}+\left[1\frac{1}{3}-5\frac{1}{2}+\frac{5}{14}\right]-\left(\frac{1}{6}-\frac{3}{7}+\frac{1}{3}\right)\)

\(-1\frac{2}{5}+\left[1\frac{3}{10}-\frac{7}{20}-1\frac{1}{4}\right]-\left(\frac{1}{5}-\left[\frac{3}{4}-1\frac{1}{2}\right]\right)\)

\(2\frac{1}{3}-\left(\frac{1}{2}-2\frac{1}{6}+\frac{3}{4}\right)+\left[\frac{5}{12}-1\frac{1}{3}\right]-\frac{7}{8}+3\frac{1}{2}\)

\(2\frac{1}{4}-1\frac{3}{5}-\left(\frac{9}{20}-\frac{7}{10}\right)+\left[1\frac{3}{5}-2\frac{1}{2}\right]+\frac{3}{4}\)

\(\left[\frac{8}{3}-5\frac{1}{4}+\frac{1}{6}\right]-\frac{7}{4}+\frac{-5}{12}-\left(1-1\frac{1}{2}+\frac{1}{3}\right)\)

\(\left(\frac{1}{4}-\left[1\frac{1}{4}-\frac{7}{10}\right]+\frac{1}{2}\right)-2\frac{1}{5}-1\frac{3}{10}+\left[1-\frac{1}{2}\right]\)

TRÌNH BÀY GIÚP MÌNH NHA 

0
1 tháng 9 2019

a, \(\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{x\left(x+1\right)}=\frac{13}{90}\)

\(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{13}{90}\)

\(\frac{1}{5}-\frac{1}{x+1}=\frac{13}{90}\)

\(\frac{1}{x+1}=\frac{1}{5}-\frac{13}{90}\)

\(\frac{1}{x+1}=\frac{18}{90}-\frac{13}{90}\)

\(\frac{1}{x+1}=\frac{1}{18}\)

⇒ x + 1 = 18

⇒ x = 17

Vậy x = 17

b, \(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}=\frac{49}{148}\)

\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{x\left(x+3\right)}=\frac{49.3}{148}\)

\(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{147}{148}\)

\(1-\frac{1}{x+3}=\frac{147}{148}\)

\(\frac{1}{x+3}=1-\frac{147}{148}\)

\(\frac{1}{x+3}=\frac{1}{148}\)

⇒ x + 3 = 148

⇒ x = 145

Vậy x = 145

4 tháng 9 2019

3,

a) (23+37):45+(13+47):45

= \(-\frac{5}{21}:\frac{4}{5}+\frac{5}{21}:\frac{4}{5}\)

= \(\left(-\frac{5}{21}+\frac{5}{21}\right):\frac{4}{5}\)

= \(0:\frac{4}{5}=0\)

4 tháng 9 2019

2,

a) \(\frac{-3}{4}\).\(\frac{12}{-5}\).(\(\frac{-25}{6}\))

= \(\frac{-3.4.3.\left(-5\right).5}{4.\left(-5\right).3.3}\)

= \(-5\)

b) (−2).\(\frac{-38}{21}\).\(\frac{-7}{4}\).(\(\frac{-3}{8}\))

= \(\frac{-2.\left(-38\right)\left(-7\right)\left(-3\right)}{\left(-7\right)\left(-3\right)\left(-2\right)\left(-2\right).8}\)

= \(\frac{19}{8}\)

c) (\(\frac{11}{12}:\frac{33}{16}\)).\(\frac{3}{5}\)

= \(\left(\frac{11}{12}.\frac{16}{33}\right).\frac{3}{5}\)

= \(\frac{4}{9}.\frac{3}{5}\)

= \(\frac{4}{15}\)

d) \(\frac{7}{23}\left[\left(\frac{-8}{6}\right)-\frac{45}{18}\right]\)

= \(\frac{7}{23}.\left(\frac{-41}{10}\right)\)

= \(\frac{-287}{203}\)

3. Tính:

a) (\(\frac{-2}{3}+\frac{3}{7}\)):\(\frac{4}{5}\)+(\(\frac{-1}{3}+\frac{4}{7}\)):\(\frac{4}{5}\)

= (\(\frac{-2}{3}+\frac{3}{7}\)\(+\)\(\frac{-1}{3}+\frac{4}{7}\)) : \(\frac{4}{5}\)

= 0 : \(\frac{4}{5}\)

= 0

b) \(\frac{5}{9}\):(\(\frac{1}{11}-\frac{5}{22}\))+\(\frac{5}{9}\):(\(\frac{1}{15}-\frac{2}{3}\))

= \(\frac{5}{9}\): \(\frac{-3}{22}\)+ \(\frac{5}{9}\): \(\frac{-3}{5}\)

= \(\frac{5}{9}\): \(\frac{-81}{110}\)

= \(\frac{-550}{729}\)

a)     \(1\frac{3}{19}+\frac{8}{21}-\frac{3}{19}+0.5+\frac{13}{21}\)

\(=\left(1\frac{3}{19}-\frac{3}{19}\right)+\left(\frac{8}{21}+\frac{13}{21}\right)+0.5\)

\(=1+1+0.5=2.5\)

b)  \(\left(-\frac{3}{4}+\frac{2}{7}\right):\frac{3}{7}+\left(\frac{5}{7}+\frac{-1}{4}\right):\frac{3}{7}\)

\(=\left(\frac{-3}{4}+\frac{2}{7}+\frac{5}{7}+\frac{-1}{4}\right):\frac{3}{7}\)

\(=0:\frac{3}{7}=0\)

17 tháng 6 2019

\(\left(-2\right).\left(\frac{-38}{21}\right).\left(\frac{-7}{4}\right).\left(\frac{3}{-8}\right)\)

\(=\frac{\left(-2\right).\left(-38\right).\left(-7\right).\left(-3\right)}{21.4.8}\)

\(=\frac{19}{8}\)

17 tháng 6 2019

\(\left(-2\right)\cdot\frac{-38}{21}\cdot\frac{-7}{4}\cdot\left(\frac{-3}{8}\right)\)

\(=\frac{-2\cdot\left(-38\right)\cdot\left(-7\right)\cdot\left(-3\right)}{21\cdot4\cdot8}=\frac{-2\cdot\left(-38\right)\cdot21}{21\cdot4\cdot8}=\frac{-2\cdot\left(-38\right)}{32}=\frac{19}{8}\)