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\(\begin{array}{l} 1,\ xFe_2O_3+(3x-2y)CO\xrightarrow{t^o} 2Fe_xO_y+(3x-2y)CO_2\uparrow\\ 2,\ C_xH_y+\bigg(x+\dfrac{y}{4}\bigg)O_2\xrightarrow{t^o} xCO_2\uparrow+\dfrac{y}{2}H_2O\end{array}\)
2Mg+O2-->2MgO
2Na+Cl2-->2NaCl
2H2+O2-->2H2O
Zn+2HCl-->ZnCl2+H2
a. 2Cu + O2 → 2CuO
b. 4Al + 3O2 → 2Al2O3
c. 2H2 +O2 → 2H2O
d. 2Na + Cl2 → 2NaCl
e. 2Al + 3Cl2 → 2AlCl3
f. Fe + 2HCl → FeCl2 + H2
g.3NaOH + AlCl3 → 2Al(OH)3 + 3NaCl
Ca + H2O \(\rightarrow\) Ca(OH)2 + H2
P2O5 + 3H2O \(\rightarrow\) 2H3PO4
2Al(OH)3 + 3H2SO4 \(\rightarrow\) Al2(SO4)3 + 6H2O
3Mg + 2AlCl3 \(\rightarrow\) 2Al + 3MgCl2
2KMnO4 + 16HCl \(\rightarrow\) 2KCl + 2MnCl2 + 5Cl2 + 8H2O
2Zn + O2 \(\rightarrow\) 2ZnO
3CO + Fe2O3 \(\rightarrow\) 2Fe + 3CO2
\(1,4Na+O_2\rightarrow^{t^o}2Na_2O\\ 2,4P+5O_2\rightarrow^{t^o}2P_2O_5\\ 3,3Fe+2O_2\rightarrow^{t^o}Fe_3O_4\\ 4,2H_2+O_2\rightarrow^{t^o}2H_2O\\ 5,N_2+H_2⇌^{\left(t^o,xt,p\right)}NH_3\\ 6,P_2O_5+3H_2O\rightarrow2H_3PO_4\\ 7,N_2O_5+H_2O\rightarrow2HNO_3\\ 8,2Al+6HCl\rightarrow2AlCl_3+3H_2\\ 9,2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\\ 10,2Cu+O_2\rightarrow^{t^o}2CuO\\ 11,CaO+2HNO_3\rightarrow Ca\left(NO_3\right)_2+H_2O\\ 12,Al\left(OH\right)_3+3HNO_3\rightarrow Al\left(NO_3\right)_3+3H_2O\\ 13,Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(P_2O_5+3H_2O\rightarrow2H_3PO_4\) (1:3:2)
\(2C_2H_2+5O_2\xrightarrow[]{t^o}4CO_2+2H_2O\) (2:5:4:2)
\(2Fe\left(OH\right)_3\xrightarrow[]{t^o}Fe_2O_3+3H_2O\) (2:1:3)
\(4Na+O_2\rightarrow2Na_2O\) (4:1:2)
\(2Mg+O_2\xrightarrow[]{t^o}2MgO\) (2:1:2)
\(2Fe+3Cl_2\xrightarrow[]{t^o}2FeCl_3\) (2:3:2)
\(Mg+2HCl\rightarrow MgCl_2+H_2\) (1:2:1:1)
\(2C_4H_{10}+13O_2\xrightarrow[]{t^o}8CO_2+10H_2O\) (2:13:8:10)
\(3NaOH+AlCl_3\rightarrow3NaCl+Al\left(OH\right)_3\) (3:1:3:1)
\(3Cu+8HNO_3\rightarrow3Cu\left(NO_3\right)_2+2NO+4H_2O\) (3:8:3:2:4)
\(2Al\left(OH\right)_3\rightarrow Al_2O_3+3H_2O\left(2:1:3\right)\)
\(2C_2H_2+5O_2\rightarrow4CO_2+2H_2O\left(2:5:4:2\right)\)
\(Ba+2H_2O\rightarrow Ba\left(OH\right)_2+H_2\left(1:2:1:1\right)\)
\(CH_4+2O_2\rightarrow CO_2+2H_2O\left(1:2:1:2\right)\)
\(1,2Ba+O_2\xrightarrow{t^o}2BaO\\ 2,Zn(OH)_2+2HCl\to ZnCl_2+2H_2O\\ 3,P_2O_5+3H_2O\to 2H_3PO_4\\ 4,C_4H_8+6O_2\xrightarrow{t^o}4CO_2+4H_2O\\ 5,2NaHCO_3+H_2SO_4\to Na_2SO_4+2H_2O+2CO_2\uparrow\\ 6,\text{Sẽ có }22\text{ phân tử }CO_2{\text{ được tạo ra}}\)
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