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6:(-27)=(\(-6\dfrac{1}{2}\))\(:29\dfrac{1}{4}\)
\(\Leftrightarrow\)6:(-27)=\(\left(-\dfrac{13}{2}\right):\dfrac{117}{4}\)
\(\Rightarrow\)\(\left(-\dfrac{13}{2}\right):\dfrac{117}{4}\)=\(\left(-\dfrac{13}{2}\right):\dfrac{4}{117}\)=\(-\dfrac{2}{9}\)
Ta có:\(\dfrac{6}{-27}=\dfrac{-2}{9}\)
hay\(\dfrac{6}{-2}=\dfrac{-27}{9}\);\(\dfrac{6}{-2}=\dfrac{27}{-9}\);\(\dfrac{2}{-9}=\dfrac{6}{-27}\)
\(\dfrac{6}{-6,5}=\dfrac{29,25}{-27};\dfrac{6,5}{6}=\dfrac{-27}{29,25}\)
a: \(\dfrac{5}{-9}=\dfrac{15}{-27};\dfrac{5}{15}=\dfrac{-9}{-27};\dfrac{-9}{5}=\dfrac{-27}{15};\dfrac{15}{5}=\dfrac{-27}{-9}\)
d: \(\dfrac{12}{15}=\dfrac{16}{20};\dfrac{12}{16}=\dfrac{15}{20};\dfrac{15}{12}=\dfrac{20}{16};\dfrac{16}{12}=\dfrac{20}{15}\)
\(1.\)
\(a,\)
\(7.\left(-28\right)=\left(-49\right).4\)
Ta có : \(\frac{7}{-49}=\frac{4}{-28}\) \(\frac{-28}{4}=\frac{-49}{7}\)
\(\frac{7}{4}=\frac{-49}{-28}\) \(\frac{-28}{-49}=\frac{4}{7}\)
\(b,\)
\(0,36.4,25=0,9.1,7\)
Ta có : \(\frac{0,36}{0,9}=\frac{1,7}{4,25}\) \(\frac{0,36}{1,7}=\frac{0,9}{4,25}\)
\(\frac{4,25}{0,9}=\frac{1,7}{0,36}\) \(\frac{4,25}{1,7}=\frac{0,9}{0,36}\)