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(x3 – 2x2 + x – 1)(5 – x)
= (x3 – 2x2 + x – 1).5 + (x3 – 2x2 + x – 1).(–x)
= x3.5 + (–2x2).5 + x.5 + (–1).5 + x3.(–x) + (–2x2).(–x) + x.(–x) + (–1).(–x)
= 5x3 – 10x2 + 5x – 5 – x4 + 2x3 – x2 + x
= –x4 + (5x3 + 2x3) – (10x2 + x2) + (5x + x) – 5
= –x4 + 7x3 – 11x2 + 6x – 5
Ta có:
(x3 – 2x2 + x – 1).(x – 5)
= (x3 – 2x2 + x – 1).[–(5 – x)]
= – (x3 – 2x2 + x – 1).(5 – x)
= – (–x4 + 7x3 – 11x2 + 6x – 5)
= x4 – 7x3 + 11x2 – 6x + 5.
a) \(\left(x^2-2x+1\right)\left(x-1\right)=\left(x-1\right)^2\left(x-1\right)=\left(x-1\right)^3=x^3-3x^2+27x-1\)
\(a,\)\(\left(x^2-2x+1\right)\left(x-1\right)\)
\(=\left(x-1\right)^2\left(x-1\right)\)
\(=\left(x-1\right)^3\)
\(=x^3-3x^2+3x-1\)
\(b,\)\(\left(x^3-2x^2+x-1\right)\left(5-x\right)\)
\(=5x^3-x^4-10x^2+2x^3+5x-x^2-5+x\)
\(-x^4+7x^3-11x^2+6x-5\)
a) 2x. (x2 – 7x -3)
= 2x3- 14x2- 6x
b) ( -2x3 + y2 -7xy). 4xy2
= -8x4y2+ 4xy4- 28x2y3
c)(-5x3).(2x2+3x-5)
= -10x5-15x4+25x3
d) (2x2 - xy+ y2).(-3x3)
=-6x5+ 3x4y -3x3y2
e)(x2 -2x+3). (x-4)
=x3-2x2+3x -4x2+8x-12
=x3-6x2+11x-12
f) ( 2x3 -3x -1). (5x+2)
=10x4-15x2-5x +4x3-6x-2
=10x4+4x3-15x2-11x-2
a: \(=x^3-x^2y^2\)
b: \(=2x^2+6x-3x-9\)
\(=2x^2+3x-9\)
x3 -2x2 + x -1
x
-x+ 5
5x3 -10x2+5x-5
-x4+ 2x3- x2 +x
-x4+7x3-11x2+6x-5
sao không àm ngang được à