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Bài giải:
a) (-2x5 + 3x2 – 4x3) : 2x2 = (- )x5 – 2 + x2 – 2 + (-)x3 – 2 = - x3 + – 2x.
b) (x3 – 2x2y + 3xy2) : (- x) = (x3 : -x) + (-2x2y : -x) + (3xy2 : -x)
= -2x2 + 4xy – 6y2
c)(3x2y2 + 6x2y3 – 12xy) : 3xy = (3x2y2 : 3xy) + (6x2y2 : 3xy) + (-12xy : 3xy)
= xy + 2xy2 – 4.
a) (-2x5+3x2-4x3) : 2x2
= (-2x5:2x2)-(4x3:2x2)+(3x2:2x2)
= -x3-2x+\(\dfrac{3}{2}\)
b) \(\left(x^3-2x^2y+3xy^2\right):\left(-\dfrac{1}{2}x\right)\)
= \(\left(x^3:\dfrac{-1}{2}x\right)+\left(-2x^2y:\dfrac{-1}{2}x\right)+\left(3xy^2:\dfrac{-1}{2}x\right)\)
= \(-2x^2+4xy-6y^2\)
c) \(\left(3x^2y^2+6x^2y^3-12xy\right):3xy\)
= \(\left(6x^2y^3:3xy\right)+\left(3x^2y^2:3xy\right)+\left(-12xy:3xy\right)\)
= \(xy^2+xy-4\)
sau bạn đăng tách ra cho mn cùng giúp nhé
a, \(\left(-2x^5+3x^2-4x^3\right):2x^2=-x^3+\frac{3}{2}-2x\)
b, \(\left(x^3-2x^2y+3xy^2\right):\left(-\frac{1}{2}x\right)=-\frac{x^2}{2}+xy-\frac{3y^2}{2}\)
c, \(\left(3x^2y^2+6x^3y^3-12xy^2\right):3xy=xy+2x^2y^2-4y\)
d, \(\left(4x^3-3x^2y+5xy^2\right):\frac{1}{2}x=2x^2-\frac{3xy}{2}+\frac{5y^2}{2}\)
e, \(\left(18x^3y^5-9x^2y^2+6xy^2\right):3xy^2=6x^2y^3-3x+2\)
f, \(\left(x^4+2x^2y^2+y^4\right):\left(x^2+y^2\right)=\left(x^2+y^2\right)^2:\left(x^2+y^2\right)=x^2+y^2\)
\(\left(8x^2y^5-2x^2y^2=3xy\right):\left(-2xy\right)\)
\(=\left[8x^2y^5:\left(-2xy\right)\right]+\left(2x^2:2xy\right)+\left[3xy:\left(-2xy\right)\right]\)
\(=-4xy^4+xy-\dfrac{3}{2}\)
`#3107.101107`
a)
`A + B =` \(x^2+5xy-3y^2\)\(+ 2x^2-3xy+11y^2\)
`= (x^2 + 2x^2) + (5xy - 3xy) + (-3y^2 + 11y^2)`
`= 3x^2 + 2xy + 8y^2`
b)
\((9x^3y^2-12x^2y+15xy) \div (3xy)\)
`= 9x^3y^2 \div 3xy - 12x^2y \div 3xy + 15xy \div 3xy`
`= 3x^2y - 4x + 5`
\(=-x^2+2xy-3y^2\)
(x^3 - 2x^2y + 3xy^2) : (-x)= -x^2+2xy-3y^2