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Nguyễn Thảo Vy · Accepted Answer

1. Tìm R₁:

$U_{23}=U_2=U_3=I_2\cdot R_2=2\cdot6=12V\left(R_2\backslash\backslash R_3\right)$

$I=I_1=I_{23}=\dfrac{U_{23}}{R_{23}}=\dfrac{12}{\dfrac{6.3}{6+3}}=6A\left(R_1ntR_{23}\right)$

$\Rightarrow R_1=\dfrac{U_1}{I_1}=\dfrac{\left(18-12\right)}{6}=1\Omega$

Câu trả lời:

1. Tìm R₁:

$U_{23}=U_2=U_3=I_2\cdot R_2=2\cdot6=12V\left(R_2\backslash\backslash R_3\right)$

$I=I_1=I_{23}=\dfrac{U_{23}}{R_{23}}=\dfrac{12}{\dfrac{6.3}{6+3}}=6A\left(R_1ntR_{23}\right)$

$\Rightarrow R_1=\dfrac{U_1}{I_1}=\dfrac{\left(18-12\right)}{6}=1\Omega$

Nguyễn Thảo Vy · Answer

2. Tìm R₃:

$U_{23}=U_2=U_3=I_2\cdot R_2=2.1=2V\left(R_2\backslash\backslash R_3\right)$

$U_1=U-U_{23}=18-2=16V$

$\rightarrow I=I_1=I_{23}=\dfrac{U_1}{R_1}=\dfrac{16}{3}=\dfrac{16}{3}A\left(R_1ntR_{23}\right)$

$\rightarrow I_3=I_{23}-I_2=\dfrac{16}{3}-2=\dfrac{10}{3}A$