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\(\text{(x−2)(2y+1)=17}\)
\(\text{⇒(x−2)(2y+1)=1.17=17.1=(−1).(−17)=(−17).(−1)}\)
Ta có bảng sau:
| x−2 | 1 | 17 | −1 | −17 |
| 2y+1 | 17 | 1 | −17 | −1 |
| x | 3 | 19 | 1 | −15 |
| y | 8 | 0 | −9 | −1 |
Vậy \(\hept{\begin{cases}x=3\\y=8\end{cases}\hept{\begin{cases}x=19\\y=0\end{cases}\hept{\begin{cases}x=1\\y=-9\end{cases}\hept{\begin{cases}x=-15\\y=-1\end{cases}}}}}\)
học tốt
trung bình mỗi xe chở đc
(4500 + 4500 + 4500 + 8000 + 8000) : (3 + 2) = 5900 (tấn)
đáp số : 5900 tấn
Vào lúc: 2016-04-11 21:24:29 Xem câu hỏi
SBT = ST + hiệu
tổng sô trừ và hiệu là:(số bị trừ)
2008 : 2 = 1004
số trừ là:
(1004 - 12) : 2 = 496
trung bình mỗi xe chở đc
(4500 + 4500 + 4500 + 8000 + 8000) : (3 + 2) = 5900 (tấn)
đáp số : 5900 tấn
Vào lúc: 2016-04-11 21:24:29 Xem câu hỏi
SBT = ST + hiệu
tổng sô trừ và hiệu là:(số bị trừ)
2008 : 2 = 1004
số trừ là:
(1004 - 12) : 2 = 496
1.2^x=4
=>2^x=2^2
=>x=2
2.2^x=8
=>2^x=2^3
=>x=3
3.2^x=16
=>2^x=2^4
=>x=4
4.2^x=32
=>2^x=2^5
=>x=5
5.2^x=64
=>2^x=2^6
=>x=6
6.2^x+1=4
=>2^x=4-1=3
=>x\(\in\phi\)
7.2^x+1=1
=>2^x=1-1=0
=>x=0
8.2^x+1=8
=>2^x=8-1=7
=>x\(\in\phi\)
9.2^x+1=16
=>2^x=16-1=15
=>x\(\in\phi\)
10.2^x+1=32
=>2^x=32-1=31
=>x\(\in\phi\)
Neu de bai sai thi cung k ung ho minh nha!Ths
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a) Để â nhận giá trị nguyên
\(\Rightarrow8n-9⋮2n+5\)
\(\Rightarrow8n+20-29⋮2n+5\)
\(\Rightarrow4.\left(2n+5\right)-29⋮2n+5\)
mà \(4.\left(2n+5\right)⋮2n+5\)
\(\Rightarrow-29⋮2n+5\)
\(\Rightarrow2n+5\inƯ\left(-29\right)\)
tự làm nốt nhé, tick nha
toi nay mk se lay y kien cua cac ban , giup mk nha
b1
a) \(\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\)
\(=\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=\dfrac{1}{5}-\dfrac{1}{10}\)
\(=\dfrac{2}{10}-\dfrac{1}{10}\)
\(=\dfrac{1}{10}\)
b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}\)
\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)
\(=\dfrac{1}{1}-\dfrac{1}{100}\)
\(=\dfrac{99}{100}\)
c) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\)
\(=\dfrac{1}{3}-\dfrac{1}{11}\)
\(=\dfrac{8}{33}\)
d) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{99.101}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\)
\(=\dfrac{1}{3}-\dfrac{1}{101}\)
\(=\dfrac{98}{303}\)
\(B=\frac{7}{15}+\frac{4}{5}-1=\frac{19}{15}-1=\frac{4}{15}\)
\(5-\frac{2}{3}+\frac{1}{5}=\frac{13}{3}+\frac{1}{5}=\frac{68}{15}\)
Đặt \(A=\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}=\frac{1}{2}-\frac{1}{2^2}+\frac{1}{2^3}-\frac{1}{2^4}+\frac{1}{2^5}-\frac{1}{2^6}\)
\(2A=1-\frac{1}{2}+\frac{1}{2^2}-\frac{1}{2^3}+\frac{1}{2^4}-\frac{1}{2^5}\)
\(2A+A=3A=1-\frac{1}{2^6}=\frac{2^6-1}{2^6}< 1\)
\(\Rightarrow3A< 1\Rightarrow A< \frac{1}{3}\)(ĐPCM)