\(\underrightarrow{+HCL}\) B \(\underri...">
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13 tháng 6 2017

A: CuCO3

B: CuCl2

C: Cu(OH)2

D: CuO

PTHH:

CuCO3 + HCl ===> CuCl2 + CO2 + H2O

CuCl2 + 2NaOH ===> Cu(OH)2 + 2NaCl

Cu(OH)2 =(nhiệt)=> CuO + H2O

CuO + CO =(nhiệt)=> Cu + CO2

13 tháng 6 2017

tks

9 tháng 7 2018

A là CuO hoặc Cu(OH)2

4 tháng 7 2018

A: Al..................................................D:Al2O3

B: Ca(AlO2)2.....................................E:AlCl3

C: Al(OH)3

Ta có các phương trình phản ứng sau:

Al + Ca(OH)2 + H2O Ca(AlO2)2 + H2

Ca(AlO2)2 + 2 HCl + 2 H2O ➞ 2 Al(OH)3 + CaCl2

2 Al(OH)3tO Al2O3 + 3 H2O

2 Al2O3 ➞(đpnc) 4 Al + 3 O2

2 Al + 3 FeO ➞ Al2O3 + 3 Fe

Al2O3 + 6 HCl ➞ 2 AlCl3 + 3 H2O

2 AlCl3 + 3 Mg ➞ 2 Al + 3 MgCl2

26 tháng 10 2019

CaO+H2O---->Ca(OH)2

Pt2 ko ổn lw

Na2CO3+2HCl----->2NaCl+H2O+CO2

2NaCl+H2SO4---->Na2SO4+2HCl

Na2SO4+BaCl2---->2NaCl+BaSO4

2NaCl+2H2O---->Cl2+H2+2NaOH

NaOH+HCl----->NaCl+H2O

2NaCl+H2SO4---->Na2SO4+2HCl

26 tháng 10 2019

PTHH:CaO+H2O---->Ca(OH)2

Na2CO3+2HCl----->2NaCl+H2O+CO2

2NaCl+H2SO4---->Na2SO4+2HCl

Na2SO4+BaCl2---->2NaCl+BaSO4

2NaCl+2H2O---->Cl2+H2+2NaOH

NaOH+HCl----->NaCl+H2O

2NaCl+H2SO4---->Na2SO4+2HCl

#Walker

2NaOH + Al2O3 ----to---> 2NaAlO2 + H­2O

NaAlO2 + CO2 + 2H2O ------> NaHCO3 + Al(OH)3

2Al(OH)3 ----to-----> Al2O3 + 3H2O

2Al2O3 ---Criolit--to---> 4Al + 3O­2

Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3 B/...
Đọc tiếp

Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3

B/ \(Na\underrightarrow{\left(1\right)}Na_2O\underrightarrow{\left(2\right)}NaOH\underrightarrow{\left(3\right)}Na_2SO_4\underrightarrow{\left(4\right)}NaCl\underrightarrow{\left(5\right)}NaNO_3\underrightarrow{\left(6\right)}NaCl\underrightarrow{\left(7\right)}NaOH\)

C/\(Mg\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgCl_2\underrightarrow{\left(3\right)}Mg\left(NO_3\right)_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgSO_4\underrightarrow{\left(6\right)}MgCO_3\)

D/\(CuSO_4\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuO\underrightarrow{\left(3\right)}CuCl_2\underrightarrow{\left(4\right)}Cu\left(OH\right)_2\underrightarrow{\left(5\right)}CuSO_4\)

E/\(CuCl_2\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuSO_4\underrightarrow{\left(3\right)}Cu\underrightarrow{\left(4\right)}CuO\)

F/ \(Cu\left(OH\right)_2\underrightarrow{\left(1\right)}CuO\underrightarrow{\left(2\right)}CuCl_2\underrightarrow{\left(3\right)}Cu\left(NO_3\right)_2\underrightarrow{\left(4\right)}NaNO_3\)

G/\(Fe_2O_3\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\)

H/ \(ZnCl_2\underrightarrow{\left(1\right)}Zn\left(OH\right)_2\underrightarrow{\left(2\right)}ZnCl_2\underrightarrow{\left(3\right)}NaCl\underrightarrow{\left(4\right)}NaNO_3\)

M/\(CuO\underrightarrow{\left(1\right)}CuCl_2\underrightarrow{\left(2\right)}Cu\left(OH\right)_2\underrightarrow{\left(3\right)}CuO\underrightarrow{\left(4\right)}CuSO_4\)

N/\(Fe\left(OH\right)_2\underrightarrow{\left(1\right)}FeO\underrightarrow{\left(2\right)}FeCl_2\underrightarrow{\left(3\right)}Fe\left(ỌH_2\right)\underrightarrow{\left(4\right)}FeSO_4\underrightarrow{\left(5\right)}FeCl_2\underrightarrow{\left(6\right)}Fe\left(NO_3\right)_2\)

Z/ \(Mg\left(OH\right)_2\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgSO_4\underrightarrow{\left(3\right)}MgCl_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgCl_2\underrightarrow{\left(6\right)}Mg\left(NO_3\right)_2\)

X/\(Al\left(OH\right)_3\underrightarrow{\left(1\right)}Al_2O_3\underrightarrow{\left(2\right)}AlCl_3\underrightarrow{\left(3\right)}Al\underrightarrow{\left(4\right)}Al_2\left(SO_4\right)_3\)

11
7 tháng 11 2018

g) 1. Fe2O3 + 6HCl → 2FeCl3 + 3H2O

2. FeCl3 + 3NaOH → 3NaCl + Fe(OH)3

3. 2Fe(OH)3 \(\underrightarrow{to}\) Fe2O3 + 3H2O

4. Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O

7 tháng 11 2018

h) 1. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2

2. Zn(OH)2 + 2HCl → ZnCl2 + 2H2O

3. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2

4. NaCl + AgNO3 → NaNO3 + AgCl↓

28 tháng 8 2018

MONG CÁC BN GIÚP MÌNH

11 tháng 9 2018

a(1),fe+2hcl->fecl2+h2 (2) fecl2+ba(oh)2->fe(oh)2+bacl2 (3)fe(oh)2+h2so4->feso4+2h20 (4)feso4+bacl2->fecl2+baso4

11 tháng 9 2018

b.(1)2fe+3cl2->2fecl3 (2)2fecl3+3ba(oh)2->2fe(oh)3+3bacl2 (3)2fe(oh)3+o2->fe2o3+h2o (4)fe2o3+3co->2fe+3co2

8 tháng 9 2019

3Fenóng đỏ +2O2\(\rightarrow\)Fe3O4

Fe3O4+ 8HCl →FeCl2+2FeCl3 +4H2O

FeCl2 + 2NaOH →→Fe(OH)2+2NaCl

FeCl3 + 3NaOH →Fe(OH)3+3NaCl

4Fe(OH)2 + O2 +H2O 4Fe(OH)3

2Fe(OH) \(\underrightarrow{to}\) Fe2O3+3H2O

11 tháng 6 2020

C2H4+H2O → C2H5OH

C2H5OH+O2 \(\underrightarrow{^{\text{men giấm}}}\) CH3COOH+H2O

CH3COOH+NaOH → CH3COONa+H2O