Question

[Kiều Tuấn Nhật Minh]

Help me plss

Answer 1

[Nguyễn Huy Tú]

a, \(A=\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{8}-\frac{5}{10}+\frac{5}{11}+\frac{5}{12}}=\frac{3}{5}\)

b, \(2^{17}+2^{14}=2^{17}\left(2^3+1\right)=9.2^{17}⋮9\)( đpcm )

Answer 2

[Lê Văn Trung (тεam ASL)]

a) A=\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}\)

A=\(\frac{\frac{3}{10}-\frac{3}{10}+\frac{36}{132}+\frac{33}{132}}{\frac{5}{10}-\frac{5}{10}+\frac{60}{132}+\frac{55}{132}}\)

A=\(\frac{69}{132}\):\(\frac{115}{132}\)

A=\(\frac{69}{115}\)

b) 2¹⁷+2¹⁴ chia hết cho 9

Ta có :\(2^{17}\)+\(2^{14}\)

         =>\(2^3\)+\(2^{14}\)+\(2^{14}\)

         =>\(2^{14}\).(8+1)

         =>\(2^{14}\).9

Vì 9 chia hết cho 9 nên \(2^{14}\).9 chia hết cho 9 

Vậy \(2^{17}\)+\(2^{14}\) chia hết cho 9