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+ Các phân số 3/4 ; 5/8 ; 4/3 ; 2/3 theo thứ tự từ bé đến lớn là: 5/8 ; 2/3 ; 3/4 ; 4/3
+ Các phân số 3/7 ; 8/14 ; 3/8 ; 8/7 theo thứ tự từ lớn đến bé là: 8/7 ; 8/14 ; 3/7 ; 3/8
TL:
a) \(\dfrac{5}{6}\);\(\dfrac{9}{8}\);\(\dfrac{17}{18}\)
b) \(\dfrac{1}{2}\);\(\dfrac{5}{8}\);\(\dfrac{3}{4}\)
a) Ta có: \(\dfrac{6}{11}=\dfrac{18}{33}\);
\(\dfrac{23}{33}=\dfrac{23}{33}\)
\(\dfrac{2}{3}=\dfrac{22}{33}\)
Do đó: \(\dfrac{6}{11}< \dfrac{2}{3}< \dfrac{23}{33}\)
b) Ta có: \(1>\dfrac{8}{9}>\dfrac{8}{11}\)
\(\dfrac{9}{8}=\dfrac{8}{8}>1\)
Do đó: \(\dfrac{9}{8}>\dfrac{8}{9}>\dfrac{8}{11}\)
a) \(\dfrac{6}{11};\dfrac{2}{3};\dfrac{23}{33}\)
b) \(\dfrac{9}{8};\dfrac{8}{9};\dfrac{8}{11}\)
\(4\dfrac{14}{15}=\dfrac{74}{15}\)
\(3\dfrac{11}{15}=\dfrac{56}{15}\)
\(4\dfrac{11}{12}=\dfrac{59}{12}\)
\(3\dfrac{13}{15}=\dfrac{58}{15}\)
Do đó: \(3\dfrac{11}{15}< 3\dfrac{13}{15}< 4\dfrac{11}{12}< 4\dfrac{14}{15}\)
\(\frac{3}{4}< \frac{3}{2}< \frac{5}{3}< \frac{5}{2}< \frac{6}{1}< \frac{29}{4}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(1\frac{1}{2};1\frac{1}{3};1\frac{1}{4};1\frac{1}{5};1\frac{1}{6};1\frac{1}{7};1\frac{1}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
Vì \(\frac{1}{2}>\frac{1}{3}>\frac{1}{4}>\frac{1}{5}>\frac{1}{6}>\frac{1}{7}>\frac{1}{8}\)
=> \(1\frac{1}{2}>1\frac{1}{3}>1\frac{1}{4}>1\frac{1}{5}>1\frac{1}{6}>1\frac{1}{7}>1\frac{1}{8}\)
Hay \(\frac{3}{2}>\frac{4}{3}>\frac{5}{4}>\frac{6}{5}>\frac{7}{6}>\frac{8}{7}>\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
`MSC:12`
`1/3 = (1xx4)/(3xx4)= 4/12`
`3/2=(3xx6)/(2xx6)=18/12`
`5/6=(5xx2)/(6xx2)=10/12`
`3/4=(3xx3)/(4xx3)=9/12`
`-> 4/12; 9/12; 10/12;18/12`
`->1/3; 3/4;5/6;3/2`
có `1/3=4/12`
`3/2=18/12`
`5/6=10/12`
`3/4=9/12`
vì `4<9<10<18`
`=>4/12<9/12<10/12<18/12`
`=>1/3<3/4<5/6<3/2`
`=>` sắp xếp: `1/3;3/4;5/6;3/2`