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a) \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}\\ \dfrac{x}{5}+\dfrac{1}{2}=\dfrac{3}{5}\\ \dfrac{x}{5}=\dfrac{3}{5}-\dfrac{1}{2}\\ \dfrac{x}{5}=\dfrac{6}{10}-\dfrac{5}{10}\\ \dfrac{x}{5}=\dfrac{1}{10}\\ \dfrac{2x}{10}=\dfrac{1}{10}\\ \Rightarrow2x=1\\ x=1:2\\ x=0,5=\dfrac{1}{2}\)
b) \(x+\dfrac{3}{15}=\dfrac{1}{3}\\ x=\dfrac{1}{3}-\dfrac{3}{15}\\ x=\dfrac{5}{15}-\dfrac{3}{15}\\ x=\dfrac{2}{15}\)
c) \(x-\dfrac{12}{4}=\dfrac{1}{2}\\ x-3=\dfrac{1}{2}\\ x=\dfrac{1}{2}+3\\ x=\dfrac{1}{2}+\dfrac{6}{2}\\ x=\dfrac{7}{2}\)
d) \(\dfrac{1}{2}x+\dfrac{1}{2}=\dfrac{5}{2}\\ \dfrac{1}{2}x=\dfrac{5}{2}-\dfrac{1}{2}\\ \dfrac{1}{2}x=2\\ x=2:\dfrac{1}{2}\\ x=4\)
a. \(\dfrac{2x+5}{10}=\dfrac{6}{10}\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\)
b. \(\dfrac{15x+3}{15}=\dfrac{5}{15}\Leftrightarrow15x=2\Leftrightarrow x=\dfrac{2}{15}\)
c. \(\dfrac{4x-12}{4}=\dfrac{2}{4}\Leftrightarrow4x=14\Leftrightarrow x=\dfrac{7}{2}\)
d. \(\dfrac{1+x}{2x}=\dfrac{5x}{2x}\Leftrightarrow-4x=-1\Leftrightarrow x=\dfrac{1}{4}\)
e. \(\dfrac{-4\left(2x-5\right)}{6\left(2x-5\right)}-\dfrac{2}{6\left(2x-5\right)}=\dfrac{9\left(2x-5\right)}{6\left(2x-5\right)}\)
\(\Leftrightarrow-8x+20-2=18x-45\)
\(\Leftrightarrow-26x=-63\Leftrightarrow x=\dfrac{63}{26}\)
h)\(\left(2x-1\right)\left(x-7\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=0\\x-7=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=7\end{cases}}\)
g) \(x^2+2x=0\)
\(\Leftrightarrow x\left(x+2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)
\(\text{a) x. (x + 2)= 0}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)
vậy_____
\(d.\left(x-5\right)\left(x^2+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x^2+1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x\in\varnothing\end{cases}}\)
Mình làm mẫu câu a còn các câu khác tương tự nha
a, x.(x+2) = 0
=> x=0 hoặc x+2=0
=> x=0 hoặc x=-2
Vậy x thuộc {-2;0}
Tk mk nha
a,45 + x = 2x e, 4x + 3x = 70
\(\Rightarrow2x-x=45\) \(\Rightarrow7x=70\)
\(\Rightarrow x=45\) \(\Rightarrow x=10\)
Vậy x = 45 Vậy x = 10
b, 2 + x - 4 = 12 f, 6x - 18 = 0
\(\Rightarrow2+x=12+4\) \(\Rightarrow6x=18\)
\(\Rightarrow2+x=16\) \(\Rightarrow x=3\)
\(\Rightarrow x=14\) Vậy x = 3
Vậy x = 14 g, 72x : 36 = 2
c, 10 + x = 5 + 2x \(\Rightarrow72x=72\)
\(\Rightarrow2x+x=10+5\) \(\Rightarrow x=1\)
\(\Rightarrow3x=15\) Vậy x = 1
\(\Rightarrow x=5\) h, 13 + x = 5 + 2x
Vậy x = 5 \(\Rightarrow2x+x=13+5\)
d, 42 - 2x = 12 \(\Rightarrow3x=18\)
\(\Rightarrow2x=42-12\) \(\Rightarrow x=6\)
\(\Rightarrow2x=30\) Vậy x = 6
\(\Rightarrow x=15\)
Vậy x = 15
45 + x = 2x
x =45
2 + x - 4 =12
x - 2 = 12
x = 14
10 +x = 5 + 2x
-x = -5
x = 5
42 - 2x = 12
-2x = -30
x = 15
4x + 3x = 70
7x = 70
x = 10
6x - 18 = 0
6x = 18
x = 3
72x : 36 = 2
72x = 72
x = 1
13 +x = 5 +2x
-x = -8
x = 8
học tốt
a: \(4x^3+12=120\)
=>\(4x^3=108\)
=>\(x^3=27=3^3\)
=>x=3
b: \(\left(x-4\right)^2=64\)
=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)
c: (x+1)^3-2=5^2
=>\(\left(x+1\right)^3=25+2=27\)
=>x+1=3
=>x=2
d: 136-(x+5)^2=100
=>(x+5)^2=36
=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
e: \(4^x=16\)
=>\(4^x=4^2\)
=>x=2
f: \(7^x\cdot3-147=0\)
=>\(3\cdot7^x=147\)
=>\(7^x=49\)
=>x=2
g: \(2^{x+3}-15=17\)
=>\(2^{x+3}=32\)
=>x+3=5
=>x=2
h: \(5^{2x-4}\cdot4=10^2\)
=>\(5^{2x-4}=\dfrac{100}{4}=25\)
=>2x-4=2
=>2x=6
=>x=3
i: (32-4x)(7-x)=0
=>(4x-32)(x-7)=0
=>4(x-8)*(x-7)=0
=>(x-8)(x-7)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)
k: (8-x)(10-2x)=0
=>(x-8)(x-5)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)
m: \(3^x+3^{x+1}=108\)
=>\(3^x+3^x\cdot3=108\)
=>\(4\cdot3^x=108\)
=>\(3^x=27\)
=>x=3
n: \(5^{x+2}+5^{x+1}=750\)
=>\(5^x\cdot25+5^x\cdot5=750\)
=>\(5^x\cdot30=750\)
=>\(5^x=25\)
=>x=2
a: =>|x+3/4|=2+1/5=11/5
=>x+3/4=11/5 hoặc x+3/4=-11/5
=>x=29/20 hoặc x=-59/20
b: (x+1/2)(2/3-2x)=0
=>x+1/2=0 hoặc 2/3-2x=0
=>x=-1/2 hoặc x=1/3
c: =>|2x-1/3|=1/6
=>2x-1/3=1/6 hoặc 2x-1/3=-1/6
=>2x=1/2 hoặc 2x=1/6
=>x=1/4 hoặc x=1/12
e: =>x+2/3=0 hoặc -2x-3/5=0
=>x=-2/3 hoặc x=-3/10
a: x(x+2)=0
=>x=0 hoặc x+2=0
=>x=0 hoặc x=-2
c: \(\Leftrightarrow x\left(x-2\right)=0\)
=>x=0 hoặc x=2
e: \(\Leftrightarrow-12x+60+21-7x=5\)
=>-19x=-76
hay x=4
g: =>30x+60+6x-30-24x=102
=>12x+30=102
=>12x=72
hay x=6